-- Bob covered a distance of (32m + 45m) = 77 meters.
-- His displacement is the straight-line distance and direction
from his starting point to his ending point.
The straight-line distance is
D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters
The direction is the angle whose tangent is (32/45) south of east.
tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.
Answer:
magnitude of the induced emf in the coil is 0.0153 V
Explanation:
Given data
no of turns = 20
area = 0.0015 m²
magnitude B1 = 4.91 T/s
magnitude B2 = 5.42 T/s
to find out
the magnitude of the induced emf in the coil
solution
we know here
emf = -n A d∅ /dt
so here n = 20 and
A = 0.0015
and d∅ = B2 - B1 = 5.42 - 4.91
d∅ = 0.51 T and dt at 1 sec
so put all value
emf = -n A d∅ /dt
emf = -20 (0.0015) 0.51 / 1
emf = - 0.0153
so magnitude of the induced emf in the coil is 0.0153 V
Answer:
Increases the greenhouse effect and increases the absorption of radiation
Explanation:
An increase in carbon dioxide increases the greenhouse effect and increases the absorption of radiation emitted from Earth's surface. Carbon dioxide has the ability to absorb radiation emitted from Earth's surface. This is because carbon dioxide is an effective heat trapping greenhouse gas.
Answer;
V = 14.7 m/s
Explanation and solution;
Vx = V cos theta
Vx = 16m/s × cos 28.08
Vx = 14.1 m/s
Vy = Vsin theta
Vy = 7.51m/s
t = d/Vx
t = 16.8m/ 14.1
t= 1.191 s
Now, find Vy at t= 1.191
Vy = Vy - gt
Vy = 7.51 - 9.81*1.191
Vy = - 4.18 m/s
V = sqrt (Vy^2 +Vx^2)
V= sqrt (4.18^2 + 14.1^2)
V= 14.7m/s
Answer:
v2 = 2.36 m/s
Explanation:
Momentum is simply the the product of mass of an object and it velocity. Generally, when object moves they have momentum . The unit for momentum is kgm/s.
During collision momentum is conserved . This means that
initial momentum = final momentum
If their is an equal and opposite reaction your momentum should be equal to your BFF.
m1 v1 = m2 v2
m1 = 65 kg
v1 = 2.0 m/s
m2 = 55 kg
v2 = ?
m1 v1 = m2 v2
65 × 2 = 55v2
130 = 55 v2
divide both sides by 55
v2 = 130/55
v2 = 2.36363636364
v2 = 2.36 m/s