The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal
How to determine the mole of glucose
Mass of glucose = 49 g
Molar mass of glucose = 180.2 g/mol
Mole of glucose = ?
Mole = mass / molar mass
Mole of glucose = 49 / 180.2
Mole of glucose = 0.272 mole
How to determine the energy released
C₆H₁₂O₆ →2C₂H₆O + 2CO₂ ΔH = -16 kcal/mol
From the balanced equation above,
1 mole of glucose released -16 kcal of energy
Therefore,
0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal
Thus, -4.4 Kcal were released from the reaction
Learn more about stoichiometry:
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The ranking of most eagles in the food chain is at the top. They are called apex predator.
The harpy eagle is one of the largest eagle there is. Common to most eagles are its sharpness of their vision. Most eagles use it to sight their predator while circling above the ground at a distance unseen by the prey. However, harpy eagles adapted a way of hunting prey which is called perch-hunting.
Perch-hunting is a way of looking for predator by scanning the trees for prey by flying in short distances from a tree to another tree. The harpy eagle developed this skill since it is hard to sight a prey in a rain forest because of the leaves and trees blocking its vision. Hence, perch-hunting is very apt for the scenario of a rain forest eagle.
Answer:
i spy with my little eye a bill nye the science guy
The answer is chlorine
That is chlorine is the green-yellowish gas that is used as a disinfecting agent.
Among the options, iodine is a solid ,bromine is liquid while fluorine and chlorine are gases.
Chlorine is greenish yellow colored gas while fluorine is pale yellow, chlorine is used as a disinfecting agent and oxidizing agent as well.
