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blsea [12.9K]
2 years ago
13

Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)

Chemistry
1 answer:
Yuri [45]2 years ago
6 0

The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

C₆H₁₂O₆ →2C₂H₆O + 2CO₂  ΔH = -16 kcal/mol

From the balanced equation above,

1 mole of glucose released -16 kcal of energy

Therefore,

0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal

Thus, -4.4 Kcal were released from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

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(2 pts) The solubility of InF3 is 4.0 x 10-2 g/100 mL. a) What is the Ksp? Include the chemical equation and Ksp expression. MW
Aleonysh [2.5K]

Answer:

a) Ksp = 7.9x10⁻¹⁰

b) Solubility is 6.31x10⁻⁶M

Explanation:

a) InF₃ in water produce:

InF₃ ⇄ In⁺³ + 3F⁻

And Ksp is defined as:

Ksp = [In⁺³] [F⁻]³

4.0x10⁻²g / 100mL of InF₃ are:

4.0x10⁻²g / 100mL ₓ (1mol / 172g) ₓ (100mL / 0.1L) = <em>2.3x10⁻³M  InF₃. </em>Thus:

[In⁺³] = 2.3x10⁻³M  InF₃ × (1 mol In⁺³ / mol InF₃) = 2.3x10⁻³M  In⁺³

[F⁻] = 2.3x10⁻³M  InF₃ × (3 mol F⁻ / mol InF₃) = 7.0x10⁻³M F⁻

Replacing these values in Ksp formula:

Ksp = [2.3x10⁻³M  In⁺³] × [7.0x10⁻³M F⁻]³ = <em>7.9x10⁻¹⁰</em>

<em></em>

b) 0.05 moles of F⁻ produce solubility of InF₃ decrease to:

7.9x10⁻¹⁰ = [x] [0.05 + 3x]³

Where x are moles of In⁺³ produced from solid InF₃ and 3x are moles of F⁻ produced from the same source. That means x is solubility in mol / L

Solving from x:

x = -0.018 → False solution, there is no negative concentrations.

x = 6.31x10⁻⁶M → Right answer.

Thus, <em>solubility is 6.31x10⁻⁶M</em>

3 0
4 years ago
What is the correct chemical equation for the reaction between methane and oxygen to produce carbon dioxide and water?
kodGreya [7K]

Answer:

The answer to your question is:   CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

Explanation:

Methane = CH₄

Oxygen = O

Carbon dioxide = CO₂

Water = H₂O

                      CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

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3 0
3 years ago
Molar mass of c16h19n305s
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Answer:

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Explanation:

According to the given situation, the calculation of molar mass is shown below:-

Data provided

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= 192 + 19.152 + 42 + 80 + 32.06

Molar mass = 365.212

Therefore for determining the molar mass we simply solve the above equation.

So, the correct answer is 365.212

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Answer:

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Answer:

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Explanation:

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