Me no see nothing dudeeeeeeee
Hey there!
HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Balance CN.
1 on the left, 2 on the right. Add a coefficient of 2 in front of HCN.
2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Balance H.
2 on the left, 2 on the right. Already balanced.
Balance SO₄.
1 on the left, 1 on the right. Already balanced.
Balance Cu.
1 on the left, 1 on the right. Already balanced.
Our final balanced equation:
2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
Hope this helps!
Answer: E
=
1.55
⋅
10
−
19
J
Explanation:
The energy transition will be equal to 1.55
⋅
10
−
1
J
.
So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition
1
λ =
R
⋅
(
1
n
2
final −
1
n
2
initial )
, where
λ
- the wavelength of the emitted photon;
R
- Rydberg's constant - 1.0974
⋅
10
7
m
−
1
;
n
final
- the final energy level - in your case equal to 3;
n
initial
- the initial energy level - in your case equal to 5.
So, you've got all you need to solve for λ
, so
1
λ =
1.0974
⋅10 7
m
−
1
⋅
(....
−152
)
1
λ
=
0.07804
⋅
10
7
m
−
1
⇒
λ
=
1.28
⋅
10
−
6
m
Since
E
=
h
c
λ
, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by
h
⋅
c
, where
h
- Planck's constant -
6.626
⋅
10
−
34
J
⋅
s
c
- the speed of light -
299,792,458 m/s
So, the transition energy for your particular transition (which is part of the Paschen Series) is
E
=
6.626
⋅
10
−
34
J
⋅
s
⋅
299,792,458
m/s
1.28
⋅
10
−
6
m
E
=
1.55
⋅
10
−
19
J
B, because that’s the simplified definition of accuracy
2Ca+O2<span>➡2CaO
You need to balance it by adding a 2 as the coefficient on the Ca, then put 2 on the products side
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