1. Which of the following equations is balanced?

What kind of Romance Novels would kids between the age of 14-18 read. Whether it is an actual book or a book made on sites like

alexdok [17]

A book series that a 14-18 year old would read could be the books by Sarah Mlynowski. A book that I have read that is really good it Gimme A Call. It is based on a girls point of view. It is fiction because of the idea that the book revolves around the character getting a call from her future self telling her to do things differently with her life. The book isn't mainly about romance, but it does have some really good topics that teens can deal with. Also, when you are looking for a romance novel keep in mind that there are different levels of romance books. There are the type of books where there is only flirting and the usual teenage dating, but then there are books with very, and I mean very, unpleasing scenes.

6 0

3 years ago

A neutral isotope has 49 neutrons and 36 electrons. Identify the element symbol of this isotope and determine the mass number an

Marta_Voda [28]

Explanation:

In an atom , the relation between the subatomic particles of the atom are given as follows -

For a neutral atom ,

Atomic number = number of protons = number of electrons ,

Mass number = number of protons + number of neutrons,

Hence , from the given information of the question,

number of neutrons = 49 ,

number of electrons = 36 ,

Hence , by using the above relation,

Atomic number = 36

number of protons = 36

Since ,

Mass number = number of protons + number of neutrons

Mass number = 36 + 49 = 85 .

By taking the help of periodic table , as atomic number = 36 ,

The elements is Krypton ( Kr )

Kr ⁸⁵₃₆

4 0

4 years ago

calculate the molar mass of a gas if 3.30 grams of the has occupies 660 ml at 735mmHg and 27 degrees C

AnnZ [28]

Use the ideal gas law PV = nRT and manipulate it to solve for n. PV/RT = n. Convert to SI units: 660ml -> 0.660 L 27 degrees -> 300 K Leave Pressure as is Use 62.36368 for R becuase you are using mmHg for Pressure. Now plug into the equation to get about 0.025928 mols. Divide the 3.30 grams by the mols to get about 127 g/mol.

8 0

3 years ago

can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g

V125BC [204]

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) 1278.50 = 6 sig figs

2) 120000 = 2 sig figs

3) 90027.00 = 7 sig figs

4) 0.0053567 = 5 sig figs

5) 670 = 2 sig figs

6) 0.00730 = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

4 0

2 years ago

g Calculate the time (in min.) required to collect 0.0760 L of oxygen gas at 298 K and 1.00 atm if 2.60 A of current flows throu

lozanna [386]

Answer:

7.67 mins.

Explanation:

Data obtained from the question include the following:

Volume (V) = 0.0760 L

Temperature (T) = 298 K

Pressure (P) = 1 atm

Current (I) = 2.60 A

Time (t) =?

Next, we shall determine the number of mole (n) of O2 contained in 0.0760 L.

This can be obtained by using the ideal gas equation as follow:

Note:

Gas constant (R) = 0.0821 atm.L/Kmol

PV = nRT

1 x 0.0760 = n x 0.0821 x 298

Divide both side by 0.0821 x 298

n = 0.0760 / (0.0821 x 298)

n = 0.0031 mole

Next, we shall determine the quantity of electricity needed to liberate 0.0031 mole of O2.

This is illustrated below:

2O²¯ + 4e —> O2

Recall:

1 faraday = 1e = 96500 C

4e = 4 x 96500 C

4e = 386000 C

From the balanced equation above,

386000 C of electricity liberated 1 mole of O2.

Therefore, X C of electricity will liberate 0.0031 mole of O2 i.e

X C = 386000 X 0.0031

X C = 1196.6 C

Therefore, 1196.6 C of electricity is needed to liberate 0.0031 mole of O2

Next, we shall determine the time taken for the process. This can be obtained as follow:

Current (I) = 2.60 A

Quantity of electricity (Q) = 1196.6 C

Time (t) =?

Q = It

1196.6 = 2.6 x t

Divide both side by 2.6

t = 1196.6/2.6

t = 460.23 secs.

Finally, we shall convert 460.23 secs to minute. This can be achieved by doing the following:

60 secs = 1 min

Therefore,

460.23 secs = 460.23/60 = 7.67 mins

Therefore, the process took 7.67 mins.

7 0

4 years ago