Answer:
Cost of each bottle of water is $7.
Explanation:
This is the case for economies of scale. When Charles produce 1 bottle of water, it costs him $1 per bottle, when 8 bottles are produced it costs him $7. The cost per bottle of water reduces as units increases.
Answer:
Sell the put option. The put option is better and advantageous .
Explanation:
The call option is trading far below the strike price and poses risk. The price may not go up to $1.25 and hence not advisable. The put option is better as we stand to make a profit margin ($1.15 / Euro) if it sells the put at he strike price immediately. Given that the difference is high, it is unlikely that the price will move against us and we shall exercise the option as soon as the margin starts reducing.
I believe so considering an average of 20 million US citizens depend on it. Hope this helps.
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>