1. Is charge 2. Is the first one
<span>Half Cell Reaction:
ClO3¯ ---> Cl2
Cl¯ ---> ClO2</span>
Balance them:
<span>10e¯ + 12H+ + 2ClO3¯ ---> Cl2 + 6H2O
2H2O + Cl¯ ---> ClO2 + 4H+ + 5e¯</span>
Answer:
Methanol is more acidic than the alkyne and will be deprotonated instead.
Explanation:
of methanol is around 15 and
of terminal alkyne is around 26.
, where
is acid dissociation constant
So, higher the acidity of an acid, higher will its
value and thereby lower will be its
value.
So, methanol is certainly stronger acid than terminal alkyne.
Hence sodium amide preferably deprotonates methanol instead of terminal alkyne.
Hence, option (A) is correct.
Elements are like loners, compounds are like couples, and mixtures are like a group of friends that can also have couples (compounds)