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sergey [27]
3 years ago
15

The formula to find a certain number in an arithmetic sequence is an=a1+d(n−1)an=a1+d(n−1) .

Mathematics
2 answers:
noname [10]3 years ago
5 0

Answer: n=\dfrac{a_n-a_1}{d}+1

Step-by-step explanation:

Given : The formula to find a certain number in an arithmetic sequence is

a_n=a_1+d(n-1), where a_n is the nth term , a_1 is the first term and d is the common difference.

To solve the formula for n , first subtract a_1 from both sides , we get

a_n-a_1=d(n-1)

Now, divide d on both sides , we get

\dfrac{a_n-a_1}{d}=n-1

Now, add 1 to the both sides , we get

\dfrac{a_n-a_1}{d}+1=n

Or

n=\dfrac{a_n-a_1}{d}+1

cluponka [151]3 years ago
4 0
The formula of arithmetic sequence is
an = a₁ + d(n - 1)

Then we need to find the formula to determine n. I reverse the equation so the 'n' will be on the left side.
a₁ + d(n - 1) = an

Then I move all the terms on the left one by one to the right side except n
a₁ + d(n - 1) = an
d(n - 1) = an - a₁
n - 1 = (an - a₁)/d
n = 1 + (an - a₁)/d

This is the formula to solve n
n = 1 + (an - a₁)/d
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Joanne's Dress Shop received an invoice dated July 25 for $1,400, with terms of 2/10, 1/15, n/60. On August 8, Joanne's Dress Sh
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The actual amount that should be credited is $757.58.

<u>Solution:</u>

Given that,

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That is,

\bold{1400\times0.98 = 1372} will close the acount on days 1-10

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And August 8 is Day 15 and falls under the 1% discount rule.

Therefore, we have to divide the partial payment by the complement of the discount rate.

\bold{\Rightarrow\frac{750}{0.99} = 757.58} from the balance, and \bold{1400.00 - 757.58 = 642.42} is due by day 60.

5 0
3 years ago
Nick currently has 7,200 points in his fantasy baseball league, which is 20% points than Adam. How many points does Adam have?
Dovator [93]
Heya!!!


Answer to your question:

Let Adam's points be x.

Nick has points =7200=20%of x+x

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Adam has 6,000 points.

Hope it helps *_*

5 0
3 years ago
if two angles are complementary then the sum of their measure is 90. if the sum of the measures of two angles is 90 then both of
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3 years ago
A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
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