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sergey [27]
4 years ago
15

The formula to find a certain number in an arithmetic sequence is an=a1+d(n−1)an=a1+d(n−1) .

Mathematics
2 answers:
noname [10]4 years ago
5 0

Answer: n=\dfrac{a_n-a_1}{d}+1

Step-by-step explanation:

Given : The formula to find a certain number in an arithmetic sequence is

a_n=a_1+d(n-1), where a_n is the nth term , a_1 is the first term and d is the common difference.

To solve the formula for n , first subtract a_1 from both sides , we get

a_n-a_1=d(n-1)

Now, divide d on both sides , we get

\dfrac{a_n-a_1}{d}=n-1

Now, add 1 to the both sides , we get

\dfrac{a_n-a_1}{d}+1=n

Or

n=\dfrac{a_n-a_1}{d}+1

cluponka [151]4 years ago
4 0
The formula of arithmetic sequence is
an = a₁ + d(n - 1)

Then we need to find the formula to determine n. I reverse the equation so the 'n' will be on the left side.
a₁ + d(n - 1) = an

Then I move all the terms on the left one by one to the right side except n
a₁ + d(n - 1) = an
d(n - 1) = an - a₁
n - 1 = (an - a₁)/d
n = 1 + (an - a₁)/d

This is the formula to solve n
n = 1 + (an - a₁)/d
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Step-by-step explanation:

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The formulae of mean and variance are :

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  Variance =   $\sigma ^2=\frac{1-p}{p^2}$

                  = $\sigma ^2=\frac{1-0.001}{0.001^2}$

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   The standard deviation is determined by the root of the variance.

    $\sigma = \sqrt{\sigma^2}$

        = $\sqrt{999,000}$ = 999.4999

b). We expect to have play lottery 1000  times to win, because the mean in part (a) is 1000.

When we win the profit is 500 - 1 = 499

When we lose, the profit is -1

Expected value of the mean μ is the summation of a product of each of the possibility x with the probability P(x).

$\mu=\Sigma\ x\ P(x)= 499 \times 0.001+(-1) \times (1-0.001)$

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Since the answer is negative, we are expected to make a loss.

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