Answer:
The factors of x² - 3·x - 18, are;
(x - 6), (x + 3)
Step-by-step explanation:
The given quadratic expression is presented as follows;
x² - 3·x - 18
To factorize the given expression, we look for two numbers, which are the constant terms in the factors, such that the sum of the numbers is -3, while the product of the numbers is -18
By examination, we have the numbers -6, and 3, which gives;
-6 + 3 = -3
-6 × 3 = -18
Therefore, we can write;
x² - 3·x - 18 = (x - 6) × (x + 3)
Which gives;
(x - 6) × (x + 3) = x² + 3·x - 6·x - 18 = x² - 3·x - 18
Therefore, the factors of the expression, x² - 3·x - 18, are (x - 6) and (x + 3)
Answer:
0.01, 0.1, 1/8, 1/5
Step-by-step explanation:
can i get the crown plz
4^(12-4x)=256 realize that 256 is 4^4 so we really have:
4^(12-4x)=4^4 taking the natural log of both sides
(12-4x)ln4=4ln4 dividing both sides by ln4
12-4x=4 subtract 12 from both sides
-4x=-8 divide both sides by -4
x=2
Answer:
s= -5
Step-by-step explanation:
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