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garik1379 [7]
3 years ago
6

Solve for x. Round to the nearest hundredth.

Mathematics
2 answers:
timama [110]3 years ago
5 0
The answer must be .x
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

Solve For X. Round To The Nearest Hundredth.

1. ln (x+11) - ln (x-3) = ln 3

Solve For X

1. 5^x = 38

2. e^0.52x = 18

3. 53 + 4e^-0.21x = 821

Solve For X To The Nearest Ten-Thousandth.

1. 10 + 4.5^x = 88

Solutions:

1.ln(x+11)-ln(x-3)=ln 3

=ln(x+11)-ln(x-3)-ln3=0

=ln(x+11)-(ln(x-3)+ln3)=0

=ln(x+11)-ln (x-3)*3 = 0

=ln(x+11)-ln (3x-9 = 0

ln(x+11)=ln (3x-9

x+11=3x-9

2x=20

x=10

1. 5^x = 38

xlog5=log38

x=log38/log5=2.26

2. e^0.52x = 18

.52x lne =ln18

lne=1

x = ln18/.52 = 5.56

3. 53 + 4e^-0.21x = 821

4e^-.21x = 821-53=768

e^-.21x = 768/4=192

-0.21x lne = ln 192

lne=1

-.21x = ln 192

x = ln 192/-.21 = -25.04

1. 10 + 4.5^x = 88

4.5^x = 88-10 = 78

x log 4.5 = log 78

x = log 78/log 4.5

x = 2.8966

Step-by-step explanation:

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