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suter [353]
3 years ago
9

4. Cuál es la aplicación de las reacciones de óxido-reducción en la vida diaria y en la industria?

Chemistry
1 answer:
12345 [234]3 years ago
3 0

Answer:

<em>Dentro de las aplicaciones de la óxido-reducción se pueden encontrar:</em>

  1. <u><em>La obtención del aluminio a partir de la alúmina y la electrolisis.</em></u>
  2. <u><em>La obtención de cloro, hidrógeno e hidróxido de sodio a partir del cloruro de sodio y la electrolisis.</em></u>
  3. <u><em>La combustión interna de un motor a gasolina u otro combustible fósil.</em></u>
  4. <u><em>Las termoeléctricas, las cuales para generar energía realizan combustión de carbón.</em></u>
  5. <u><em>La galvanoplastia, donde para evitar la corrosión de un metal se recubre con otro metal más resistente, por ejemplo: el recubrimiento del acero con zinc.</em></u>
  6. <u><em>La pilas o baterías de las cuales se obtiene energía química</em></u><em>.</em>

Explanation:

<em>Como puedes ver en la respuesta, la óxido-reducción tiene diversas aplicaciones en la vida moderna, desde todos los tipos de combustión los cuales sirven para brindar energía o movilizarte, hasta todas las funciones que se le ha dado a la electrolisis y a la obtención de la energía por medios químicos, incluso se puede considerar una aplicación de la óxido-reducción la incorporación de antioxidantes en los alimentos, los cuales disminuyen la velocidad de descomposición de los mismos. </em>

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C3H8 + 5 O2 → 3 CO2 + 4 H2O
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Answer:

Mass = 112 g

Explanation:

Given data:

Mass of CO₂ produced = 90.6 g

Mass of oxygen needed = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂       →      3CO₂+ 4H₂O

Number of moles of CO₂:

Number of moles = 90.6 g/ 44 g/mol

Number of moles = 2.1 mol

Now we will compare the moles of  CO₂ and oxygen:

                 CO₂           :           O₂

                    3             :            5

                    2.1           :        5/3×2.1 = 3.5

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 3.5 mol × 32 g/mol

Mass = 112 g

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It has been suggested that hydrogen gas obtained by the decomposition of water might be a substitute for natural gas (principall
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Answer:

Hydrogen: -141 kJ/g

Methane: -55kJ/g

The energy released per gram of hydrogen in its combustion is higher than the energy released per gram of methane in its combustion.

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According to the law of conservation of the energy, the sum of the heat released by the combustion and the heat absorbed by the bomb calorimeter is zero.

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We can calculate the heat absorbed by the bomb calorimeter using the following expression.

Q = C . ΔT

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The heat released per gram of hydrogen is:

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The heat released per gram of methane is:

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