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1 answer:
Answer:
1s² 2s²2p³
Explanation:
If the atom has seven electrons, it is Element 7 (nitrogen).
In the Periodic Table, you count the electrons in all the subshells up to
No. 7.
In the first Period, you have filled the 1s level (2 electrons).
In the second Period, you have filled the 2s subshell (2 electrons) and put three electrons in the 2p subshell.
Thus, the electron configuration is
1s² 2s²2p³
Note how the superscripts tell you the number of electrons in each subshell: <em>2 + 2 + 3 = 7</em>.
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<h2>The compound formed is NaCl and 
</h2>
Explanation:
PART 1:
- Atomic number of sodium is 11.
- Sodium(Na, Z = 11, Group 1A) will lose 1 electron to become
which is isoelectronic to Neon (Ne ,Z = 10).
- The symbol for the sodium ion is
.
- Chlorine atom (
, Z = 17, Group 7A or 17) gains 1 elecron to be isoelectronic to neon.
- The symbol for the compound formed is NaCl.
- PART 2:
- Atomic number of calcium is 20
- Calcium(Ca, Z = 20 ,Group 2A) will lose two electrons to become
which is isoelectronic to argon.
- The symbol for the ion is
- Two chlorine atoms (Cl, Z = 17, Group 7A or 17) each gains one electron to be isoelectronic to argon(Z = 18)
- The symbol for the compound formed is