Cost of each pound of dog food = $2 .
Total cost of 9 pounds of dog food = 9 * 2 = $18.
Let us assume number of treats she can buy = t.
Cost of each treat = $1.
Cost of t number of treats = 1*t = 1t .
Total money Cara has = $25.
We can setup an inequality as,
Total cost of dog food + total cost of t number of treats ≤ 25.
18 + 1t ≤ 25.
Subtracting 18 from both sides, we get
18 + 1t -18 ≤ 25-18.
1t ≤ 7 or t ≤ 7.
So, she can purchase 7 or less treats.
Step-by-step explanation:
Sin: 2 square root 3: 4
Cos: 2:4
Tan: 2 square root 3: 2
Answer:
k = -13/3
Step-by-step explanation:
Step 1: Flip the equation.
k + 7/3 = -2
Step 2: Subtract 7/3 from both sides.
k+ 7/3-7/3 = -2 - 7/3
k= -13/3
Hope this helps!
Answer:
m=1/300 du
Step-by-step explanation:
we have that m=∫∫rho(x,y)dA for this we must find the limits of integration (according to the graph1)
On the x axis: if y=2x and x+2y=1 then y=2x and y=(1-x)/2 ⇒ 2x=(1-x)/2 ⇒ 4x=1-x ⇒ 5x=1 ⇒ x=1/5; on the y axis y=0 and y=1/2
m=∫∫rho(x,y)dA (view the graph 2)