Given that

, we have for

the Taylor series expansion about 0 as

Replace

with

, so that the series is equivalent to

and notice that

Recall that for

, we have

which means

9/2 = 81/a....9 kids meals to 2 adult meals = 81 kids meals to a adult meals
cross multiply
9a = 2(81)
9a = 162
a = 162/9
a = 18...so there were 18 adult meals
ratio is : 81/18
Answer:
Step-by-step explanation:
<h2><u>☼︎</u><u>Answer:</u></h2>
The cost price of cow = Rs.80
Explanation:
<h2><u>☼︎</u><u>Given :-</u></h2>
- By selling a cow for Rs 144, there is a profit of the same percentage as its cost price.
<h2><u>☼︎</u><u>T</u><u>o Find</u><u>:</u><u>-</u></h2>
<h2 /><h2 /><h2><u>☼︎</u><u>L</u><u>e</u><u>t</u><u>:</u><u>-</u></h2>
- The cost price of cow = Rs.x
<h2><u>☼︎</u><u>Solution :-</u></h2>

<h2><u>Hence: </u></h2>
The cost price of cow =<u>R</u><u>s</u><u>8</u><u>0</u>
Answer:
The answer to your question is 116.53 ft
Step-by-step explanation:
Data
length = 29 ft
width = 21 ft
π = 3.14
Process
1.- Calculate perimeter of the rectangle and subtract 1 length
Perimeter of the rectangle = 2l + 2w - l
Perimeter of the rectangle = 2(29) + 2(21) - 29
= 58 + 42 - 29
= 71 ft
2.- Calculate the perimeter of a semicircle
Perimeter = 2πr/2 = πr
radius = r = 29/2
= 14.5 ft
Perimeter = (3.14)(14.5)
= 45.53 ft
3.- Calculate the total length of the fence
fence = 45.53 + 71
= 116.53 ft