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stepladder [879]
2 years ago
11

Matthew is 3 times as old as jenny. in 7 years, he will be twice as old as she will be then. how old is each now? Explain how to

solve it to plz
Mathematics
1 answer:
Nataliya [291]2 years ago
7 0

Let m and j be the current ages of Matthew and Jenny, respectively.

Now, Matthew is 3 times as old as Jenny, so the variables are in the following relation:

m=3j

In 7 years, both of them will be 7 years older, i.e. their ages will be m+7 and j+7, and Matthew will be twice as old:

m+7=2(j+7)

Now, remembering that m=3j, we can rewrite the second equation as

3j+7=2j+14 \iff j = 7

So, Jenny is 7 and Matthew is 21 (he's 3 times older).

In fact, in 7 years, they will be 14 and 28, and Matthew will be twice as old.

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The measure of position called the midquartile of a data set is found using the formula StartFraction Upper Q 1 plus Upper Q 3 O
irinina [24]

Answer:

35.25

Step-by-step explanation:

Give the data set:

23 37 49 34 35 41 40 26 32 22 38 42

We are expected to calculate the midquartile of the given data set.

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First step is to find the lower quartile which comprises of

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Here the Q1 is (26+32)/2 = 58/2= 29

Second step to find the upper quartile which comprises of

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Here the Q3 is (40+41) /2 = 81/2 = 41.5

Then to find the midquartile which is (Q1+Q3) /2 where Q1 is 29 and Q3 is 41.5

= (29+41.5)/2

= (70.5) /2 = 35.25

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3 years ago
A 15% tip on a dinner bill is $2.55.<br> How much is the bill?
Bogdan [553]
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4 0
2 years ago
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y and x have a proportional relationship, and y = 7 when x = 2. What is the value of x when y = 21? Enter your answer in the box
Jlenok [28]
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