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MAVERICK [17]
3 years ago
9

Which is the graph of the following equation?

Mathematics
1 answer:
masha68 [24]3 years ago
7 0
Graph D is the answer to this question
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A car that retails for $14,999 has a sticker on the windshield that says, "$429/mo for 48 months." What interest rate is this ca
kkurt [141]
14,999(1+.o825)^4= 20,595. $429x48 months= 20,592
Interest rate 8 1/4%

Check 20592/14999= 1.37289
Log(1.37289)/ log(1.0825)= 3.99 years
4 0
3 years ago
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Ashley started the year with 45 comic books. Each month , she adds 5 more comic books to her collection. Which table correctly r
dybincka [34]
Ashley starts with 45 comics. 

So in the first box: 
x  = 0, y = 45
-------------------------------------------------------------------------------------------------------
Each month, she adds 5 comic books to her collection

x (+1), y (+5) (for each month).

First month. 

x = 0
y = 45

Second month

x = 1
y = 45 (+5) = 50

Third month

x = 2
y = 50 (+5) = 55

etc.

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B) is your best choice, as for every month add (+1), the comic books increase by 5 respectively.

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hope this helps

7 0
3 years ago
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Help pls i dont know
Oksana_A [137]
I'm sorry the picture is blurry. Could you post another one.
7 0
3 years ago
What is the first step in solving the quadratic equation x2 = StartFraction 9 Over 16 EndFraction? Take the square root of both
balu736 [363]

Answer:

The first step is

Take the square root of both sides of the equation

Step-by-step explanation:

we have

x^{2} =\frac{9}{16}

Solve for x

step 1

Take square root both sides

x=(+/-)\frac{3}{4}

the solutions are

x=+\frac{3}{4} and  x=-\frac{3}{4}

therefore

The first step is

Take the square root of both sides of the equation

5 0
3 years ago
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How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
\\\\\\
\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
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