Answer:
none (0) ...
think of two lines (or chop sticks places on a table) ...
there are three (3) possible orientations that they can be in.
1) they cross each other at one point
2) they are on top of each other (they touch everywhere)
3) they are side by side (parallel)
in situation one we say we have a solution
in situation two we say there is an infinite solutions (the same line)
in situation three (your problem) we say there is no solution (parallel lines)
Step-by-step explanation:
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
There are infinitely many solutions.
Algebraically, we can eliminate 
and try to solve for 
:
Then
which is the equation of an ellipse.
Question 1 is A DEBIT CARD
Question 2 is A CHECKING ACCOUNT
Answer:
20
Step-by-step explanation:
Simplify both sides of the equation.
−4=
r
20
−5
−4=
1
/20
r+−5
−4=
1
/20
r−5
Flip the equation.
1
/20
r−5=−4
Add 5 to both sides.
1
/20
r−5+5=−4+5
1
/20
r=1
Multiply both sides by 20.
20*(
1
/20
r)=(20)*(1)
r=20
