What two numbers multiply to 11 and add to -16

2 answers:

5 0

They're irrational numbers, so they can't be exactly written down.
Rounded to the nearest thousandth, they are

- 15.280
and
- 0.720 .

34kurt3 years ago

3 0

The answers are 1 and 11

You might be interested in

NIGEL is looking to buy a TV. The space that NIGEL has available for a TV is 60 inches wide and 50 inches tall. A TV's size is a

kaheart [24]

Answer:

110 inches wide

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What is the expression 3(x+6)+21+14x in simplest combined form

kolezko [41]

Answer:

Step-by-step explanation:

5 0

3 years ago

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation