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avanturin [10]
3 years ago
9

Solar energy travels to the Earth in many forms, such as ultraviolet radiation, infrared radiation, and visible rays. These vari

ous forms of solar energy have what?
Chemistry
1 answer:
galben [10]3 years ago
4 0
Radiation. Hope this Helps


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A common form of abuse of amphetamines that can damage the body is
jok3333 [9.3K]
Child abuse would be the best answer as child abuse is a common form of abuse
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3 years ago
A 15.0 L tank of gas is contained at a high pressure of
Inessa05 [86]

Answer:

20.5 torr

Explanation:

Given parameters:

Volume of tank  = 15L

Pressure of tank  = 8.2 x 10⁴torr

Volume of empty chamber = 6.0 x 10⁴L

Unknown:

New pressure of the gas in this chamber = ?

Solution:

To solve this problem, a good knowledge of the gas law will suffice here. Since pressure and volume relationships are under consideration, the Boyle's law is the proper gas law to apply.

 Boyle's law states that "at constant temperature, the volume of fixed mass of gas is inversely proportional to the pressure of the gas".

Mathematically;

    (Pressure x volume) of tank  = (Pressure x volume ) of empty chamber

      15 x 8.2 x 10⁴   = Pressure of empty chamber x 6 x 10⁴

 Pressure of empty chamber = 20.5 torr

7 0
3 years ago
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Rom4ik [11]

3,5, and 1 i think maybe i uhm yeah

7 0
3 years ago
What kind of phase transition will occur when energy is continuously supplied to a solid sample?
Annette [7]
The correct answer should be C. Melting because if energy such as thermal energy is supplied to a solid such as ice then it would melt
5 0
3 years ago
Read 2 more answers
55.2 mL of 0.500 M potassium hydroxide is used to neutralize 27.4 mL of sulfuric
mr Goodwill [35]

Answer:

0.504 M

Explanation:

Step 1: Write the balanced neutralization reaction

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

Step 2: Calculate the reacting moles of KOH

55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:

0.0552 L × 0.500 mol/L = 0.0276 mol

Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol

Step 4: Calculate the concentration of H₂SO₄

0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:

[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M

6 0
3 years ago
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