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4 years ago

2. What is the electron configuration of an electrically neutral atom of magnesium?

Chemistry

1 answer:

alekssr [168]4 years ago

7 0

Are u talking about electron sublevel config or where the electrons show in the "rings" of the atom

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How is beryllium (Be) similar to calcium (Ca)?

timofeeve [1]

C both are very reactive i guess

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4 years ago

In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibri

V125BC [204]

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

Acetic acid + Isopentyl alcohol ------> Isopentyl acetate + water

I 8M 4M 0 0

C 8-x 4-x +x +x

E 8-x 4-x +x +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2 = x^2 / 32 - 8x - 4x + x^2

x = 3.4

Concentration of acetic acid = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

Learn more about equilibrium expression

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2 years ago

Which elements make up a water molecule?

shutvik [7]

Answer:

Hydrogen and Oxygen

Explanation:

also it can be written as H2O

3 0

3 years ago

Read 2 more answers

What is the smallest component or the most basic building block of any element ? A. An Atom, B.a compound C.gas D.element

poizon [28]

The answer to the question is A) an atom.

4 0

4 years ago

For a particular isomer of C8H18, the combustion reaction produces 5113.3 kJ of heat per mole of C8H18(g) consumed, under standa

mart [117]

Answer: The standard enthalpy of formation of this isomer of $C_8H_{18}(g)$ is -210.9 kJ

Explanation:

The given balanced chemical reaction is,

$C_8H_{18}(g)+\frac{25}{2}O_2(g)\rightarrow 8CO_2(g)+9H_2O(g)$

First we have to calculate the enthalpy of formation of $C_8H_{18}$ .

$\Delta H^o=H_f_{product}-H_f_{reactant}$

$\Delta H^o=[n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{O_2}\times \Delta H_f^0_{(O_2)+n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})}]$

where,

We are given:

$\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g)))}=0kJ/mol$

Putting values in above equation, we get:

$-511.3kJ/mol=[(8\times -393.5)+(9\times -241.8)]-[(\frac{25}{2}\times 0)+(1\times \Delta H_f^0_{(C_8H_{18})}$

$\Delta H_f^0_{(C_8H_{18})}=-210.9kJ$

7 0

4 years ago

Read 2 more answers