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Whitepunk [10]
3 years ago
6

Particles of a liquid

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0
Particles of a liquid "<span> are free to move in a container but remain in close contact with one another"

In short, Your Answer would be Option D

Hope this helps!</span>
Rashid [163]3 years ago
5 0

Answer:

the answer is D.

Explanation:

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SVETLANKA909090 [29]

The mass of the blimp is 1.12 kg.

<em>Step 1</em>. Calculate the<em> volume of the blimp</em>.

<em>V</em> = 6.28 × 10⁹ mm³ × (1 m/1000 mm)³ = 6.28 m³

<em>Step 2</em>. Calculate the <em>mass of the helium</em>.

Mass = 6.28 m³ × (0.1786 kg/1 m³) = 1.12 kg

3 0
3 years ago
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The amount of heat released by the complete burning of 1 mole of a substance is the ____.
Tom [10]
The answer is specific heat
3 0
3 years ago
SYNTHESIS OFCARBONATECTIONLABORATORY SIMULATIONLab Data- X99.00.10CollectedVolume sodium carbonate (mL)Molarity sodium carbonate
evablogger [386]

Answer:

\begin{gathered} \text{Limiting Reagent = Sodium Carbonate} \\ \text{Percent Yield = 98\%} \end{gathered}

Explanation:

The chemical reaction talks about the synthesis of calcium carbonate

It is from the reaction between sodium carbonate and calcium chloride

Let us write the equation of reaction as follows:

Na_2CO_{3(aq)}+CaCl_{2(aq)}\text{ }\rightarrow2NaCl_{(s)\text{ }}+CaCO_{3(aq)}

Firstly, we want to get the expected mass of calcium carbonate

This speaks about getting the theoretical yield based on the equation of reaction

From the data collected, 90 ml of 0.20 M (mol/L) of sodium carbonate gave calcium carbonate

We need to get the actual number of moles of sodium carbonate that reacted

We can get this by multiplying the volume by the molarity (kindly note that we have to convert the volume to Liters by dividing by 1000)

Thus, we have it as:

\frac{90}{1000}\times\text{ 0.1 = 0.009 moles}

Hence, we see that 0.009 moles of sodium carbonate reacted theoretically

Since 1 mole of sodium carbonate gave 1 mole calcium carbonate, it is expected that 0.009 mole of sodium carbonate will give 0.009mole of calcium carbonate

What we have to do now is to get the theoretical grams of calcium carbonate produced

That would be the product of the number of moles of calcium carbonate and its molar mass

The molar mass of calcium carbonate is 100 g/mol

The theoretical yield (expected mass) is thus:

100\text{ g/ mol }\times\text{ 0.009mol = 0.9 g}

Finally, we proceed to get the percentage yield which is calculated using the formula below:

\text{Percent Yield = }\frac{Actual\text{ yield}}{\text{Theoretical yield}}\times\text{ 100 \%}

The actual yield is the observed mass which is given as 0.88 g

The percent yield is thus:

\frac{0.88}{0.9}\times\text{ 100 = }98\text{ \%}

7 0
1 year ago
Which type of particles have no definate shape, but they do have a definite volume?
Anna35 [415]
Liquid, liquids have a definite volume but can take the shape of whatever container holds them.
6 0
3 years ago
Sarah measures out 151 grams of SO2. How many miles is this? Express your answer to three significant figures
elena-s [515]

150 g SO₂ = 2.36 mol SO₂

M_r = 32.06 + 2×16.00 = 32.07 + 32.00 = 64.06

Moles of SO₂ = 151 g SO₂ × [1 mol SO₂/64.06 g SO₂] = 2.36 mol SO₂

6 0
3 years ago
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