Dipole-dipole interactions, and London dispersion interactions
X

H has a positive 1 charge. This means that having 3H = +3<span>. This is a neutral compound so x= -3 because X+3H= 0
Y</span>

is also neutral so 2X+Y= 0
we know X=-3 So, 2(-3)+Y=0
-6+y=0
Y=+6 charge
Answer: The valency of X is -3.
The valency of Y is 6
D=m/V
1.027g/mL=m/15.0L
1.027g/mL(1000mL/L)=1027g/L=m/15.0L
m=1027g/L15.0L
m=15405g
Answer:
The Percent composition of isopropanol in the mixture is 29.07 %
Explanation:
Step 1: Data given
Number of moles isopropanol (C3H8O) = 2.52 moles
Mass of the solution = 521 grams
Molar mass of isopropanol (C3H8O) = 60.1 g/mol
Step 2: Calculate mass of isopropanol
Mass isopropanol = moles isopropanol * molar mass isopropanol
Mass isopropanol = 2.52 moles * 60.1 g/mol
Mass isopropanol = 151.45 grams
Step 3: Calculate the percent composition of isopropanol in the mixture
Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %
Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %
Percent composition of isopropanol = 29.07 %
The Percent composition of isopropanol in the mixture is 29.07 %
Answer:
8.757 x 10^23 molecules
Explanation:
Use Avogadro's number of 6.022
×
10
^23 molecules per mole.
64g CO2/44.01 g/mol = 1.454 moles of CO2
1.454 x 6.022
×
10
^23 =
8.757 x 10^23 molecules