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Fofino [41]
3 years ago
8

If you doubled the volume of a sample of gas and then doubled the volume again without changing its pressure, how would the abso

lute temperature of the gas be affected?
Chemistry
2 answers:
Vikentia [17]3 years ago
7 0
Absolute temperature will increase fourfold<span />
djyliett [7]3 years ago
3 0

Answer:

abslute tempature will increase fourfold

Explanation:

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What is the main intermolecular force in H2CO?
aivan3 [116]
Dipole-dipole interactions, and London dispersion interactions
5 0
4 years ago
An element X forms a compound XH 3 with hydrogen. Another element Y forms a compound YX 2 with X. Given that the valency of hydr
Marina CMI [18]
XH_{3}
H has a positive 1 charge. This means that having 3H = +3<span>.  This is a neutral compound so x= -3 because X+3H= 0

Y</span>X_{2} is also neutral so 2X+Y= 0
we know X=-3 So, 2(-3)+Y=0
-6+y=0
Y=+6 charge

 
Answer: The valency of X is -3. The valency of Y is 6
7 0
3 years ago
A bucket contains 15.0 L of seawater. The density of seawater is 1.027 g/mL.
Ad libitum [116K]
D=m/V
1.027g/mL=m/15.0L
1.027g/mL(1000mL/L)=1027g/L=m/15.0L
m=1027g/L15.0L
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6 0
3 years ago
You have a solution with 2.52 moles of isopropanol (C3H8O). The solution weighs 521 grams. What is the percent composition of is
Kamila [148]

Answer:

The Percent composition of isopropanol in the mixture is 29.07 %

Explanation:

Step 1: Data given

Number of moles isopropanol (C3H8O) = 2.52 moles

Mass of the solution = 521 grams

Molar mass of isopropanol (C3H8O) = 60.1 g/mol

Step 2: Calculate mass of isopropanol

Mass isopropanol = moles isopropanol * molar mass isopropanol

Mass isopropanol = 2.52 moles * 60.1 g/mol

Mass isopropanol = 151.45 grams

Step 3: Calculate the percent composition of isopropanol in the mixture

Percent composition of isopropanol = (mass isopropanol / total mass of mixture) * 100 %

Percent composition of isopropanol = (151.45 grams / 521 grams ) * 100 %

Percent composition of isopropanol = 29.07 %

The Percent composition of isopropanol in the mixture is 29.07 %

8 0
4 years ago
Read 2 more answers
How many molecules do you have in 64 g of CO2?
Nadusha1986 [10]

Answer:

8.757 x 10^23 molecules

Explanation:

Use Avogadro's number of  6.022 × 10 ^23  molecules per mole.

64g CO2/44.01 g/mol = 1.454 moles of CO2

1.454 x  6.022 × 10 ^23 =

8.757 x 10^23 molecules

6 0
3 years ago
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