Answer:
The concentration of the Cu²⁺ solution in the 10,0 mL volumetric flask is 5,425×10⁻³ M Cu²⁺
Explanation:
The first dilution from a 2,17M Cu²⁺ solution gives:
2,17 M Cu²⁺ ×
= <em>0,0217 M Cu²⁺solution</em>
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The second dilution gives as concentration:
0,0217 M Cu²⁺ ×
= 5,425×10⁻³ M Cu²⁺ solution
I hope it helps!
Answer:
If the hydrated salt is overheated, it causes the anhydrous salt to decompose, causing the product to be lost as gas. The reported percentage of water loss will be too high because the gap between the initial measurement and final (which will be lower due to loss of sample) measurement will widen.
Where the width is narrow and the bottom steep
The answer is B I hope this helps you
