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lara [203]
3 years ago
13

Twice a number is twenty-eight

Mathematics
1 answer:
Alla [95]3 years ago
4 0
Let, the number = n
It would be: 2n = 28
n = 28/2
n = 14

In short, Your Answer would be 14

Hope this helps!
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If f(z)=m^z - n^z, and f(1)=2, f(2)=8. Find f(3).
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If f(z)=m^z - n^z <span>and f(1)=2, f(2)=8
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substitute </span>m = n + 2  into m^2 - n^2 = 8

so
m^2 - n^2 = 8
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m = n + 2 = 1 + 2 = 3

so f(z) = 3^z - 1^z

if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26

answer
f(3) = 26

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