I NEED HELP!!! Thank you so much (:

Mathematics

1 answer:

elena-s [515]3 years ago

3 0

It is C. y= |x-5|-4 because it is shifted 5 units to the right and 4 units down

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_+6 +2 = 6 + 10<br><br> Find the missing number

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574=30303 equals that

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If a point has a negative x-coordinate, and its y-coordinate is positive, where does the point lie relative to the origin? Expla

Daniel [21]

If a coordinate has a negative x-coordinate and its y-coordinate is positive, then the point is on the 2nd quadrant.
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Maurinko [17]

Hello from MrBillDoesMath!

Answer:

x = 1/2 (1 +\- i sqrt(23))

Discussion:

x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)

1 \3x - 4 = (1/3)x - 4 (**)

(*) = (**) =>

(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3

x^2 - 6 = x - 12 => subtract x from both sides

x^2 -x -6 = -12 => add 12 to both sides

x^2-x +6 = 0

Using the quadratic formula gives:

x = 1/2 (1 +\- i sqrt(23))

Thank you,

MrB

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3 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$