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3 years ago

What is the order pair for the question y=-3x-3

Mathematics

1 answer:

posledela3 years ago

4 0

Answer:

You get two, (0,-3) and (1,0)

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Algebra 1. please help me. i’m literally struggling , i’ll give an extra 50 points if it’s right and brainliest. - question in p

Arada [10]

Answer:

15x² - 3x - 7

Step-by-step explanation:

(12x² + 2x) - (-3x²+ 5x + 7)

First open the parentheses by applying the distributive property.

To do this, multiply each term you have inside (-3x⅔ + 5x + 7) by -1.

Thus, you would have the following:

12x² + 2x + 3x² - 5x - 7

Add like terms

12x² + 3x² + 2x - 5x - 7

15x² - 3x - 7

6 0

3 years ago

Find the distance between the point (-6, 7) and (-1, -2)

Anton [14]

(-5,9) because -6—1=-6+1 which equals -5 and 7—2=7+2 which equals 9

8 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago

Solve the triangle. Round your answers to the nearest tenth.

wel

Answer:

m∠A ≈ 43°

m∠B ≈ 55°

mBC ≈ 20

Step-by-step explanation:

Law of Sines: $\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Step 1: Find m∠B

$\frac{29}{sin82} =\frac{24}{sinB}$

Step 2: Solve for ∠B

29sinB = 24sin82°

sinB = 24sin82°/29

B = sin⁻¹(24sin82°/29)

B = 55.038°

Step 3: Find m∠A

180 - (55.038 + 82)

180 - 137.038

m∠A = 42.962°

Step 4: Find BC

$\frac{29}{sin82} =\frac{BC}{sin42.962}$

Step 5: Solve for BC

29sin42.962° = BCsin82°

BC = 29sin42.962°/sin82°

BC = 19.9581

4 0

3 years ago

The altitude (i.e., height) of a triangle is increasing at a rate of 2 cm/minute while the area of the triangle is increasing at

s344n2d4d5 [400]

Answer:

A = 1/2 B H area = 1/2 base X height

B = 2 A / H = 2 * 99 / 12 = 16.5 cm

dA / d t = 1/2 * (B dH / dt + H dB / dt)

dB / dt = (2 dA / dt - B dH / dt) / H

dB / dt = (2 * 1.5 cm^2 / min - 16.5 cm * 2 cm / min) / 12 cm

dB / dt = (3 - 33) / 12 cm/min = -2.5 cm/min

4 0

3 years ago