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babymother [125]
3 years ago
6

El precio de cada acción de una empresa de tecnología ha presentado a través del tiempo un comportamiento dado por la siguiente

función:
Donde t es el tiempo dado en días y A es el precio de la acción inicial cuando t = 0. Un inversionista desea conocer el número de días para el cual el valor de la acción se duplica. Para conocer este resultado, el proceso que se debe realizar es reemplazar f(t) por


A.
A/2, luego, expresar la ecuación en forma de logaritmo natural y ahora despejar t.

B.
2A, luego, expresar la ecuación en forma de logaritmo natural y ahora despejar t.

C.
2A, luego, dividir ambos lados de la ecuación por e y ahora despejar t.

D.
A/2, luego, dividir ambos lados de la ecuación por e y ahora despejar t.
Mathematics
1 answer:
Rainbow [258]3 years ago
6 0

I will ask you to turn it in english instead of española.

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A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at ​​ (−2,
Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.  

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}  

\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}

\text{Distance between vertex A and vertex B}=\sqrt{64}=8

Now let us find distance between vertex B and vertex C.

\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}

\text{Distance between vertex B and vertex C}=\sqrt{25}=5

Now let us find distance between vertex C and vertex D.

\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}

\text{Distance between vertex C and vertex D}=\sqrt{64}=8

Now let us find distance between vertex D and vertex A.

\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}  

\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}    

\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}

\text{Distance between vertex D and vertex A}=\sqrt{25}=5

Now let us add all these distances to find the total distance walked by Jared.  

\text{Total distance walked by Jared}=8+5+8+5

\text{Total distance walked by Jared}=26  

Since we have been given that one unit on the grid equals 1 yard,   therefore, Jared walked a distance equal to 26 yards.  

3 0
3 years ago
Which question is statistical? What type of paper is the best for making greeting cards? What is the name of the day of the week
Zanzabum
It is C, "What type of paper are most greeting cards made with."
4 0
3 years ago
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A(n) _____ is a two dimensional diagram that can be folded to form a three dimensional figure?
bazaltina [42]
C an isometric drawing
6 0
3 years ago
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What is the justification for step 2 in the solution process?12 - x = 7x +32Step 1: -X = 7x + 20Step 2: -8x = 20
HACTEHA [7]
Answer:

The subtraction property of equality

Option A is correct

Explanation:

The given equation is:

12 - x = 7x + 32

Subtract 12 from both sides

12 - 12 - x = 7x + 32 - 12

-x = 7x + 20 (Step 1)

From step 1 above, subtract 7x from both sides

-x - 7x = 7x - 7x + 20

-8x = 20 (Step 2)

Since we subtracted 7x from both sides to get step 2, the justification for step 2 is the subtraction property of equality

6 0
2 years ago
the equation 3s equals 21 can be used to find the number of students s in each van on a field trip how many students are in each
Leno4ka [110]

Answer:

to be honest I don't know sorry

5 0
3 years ago
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