Answer:
Explanation:To convert from cal/(g*C) to J/(kg*K), we just need to find a conversion factor for specific heat. There is really no mathematical way to do this other than to look in a physics or chemistry book and find a conversion factor. After doing this, you will see that 1 cal/(g*C) is equal to 4,186 J/(kg*K).
To find the specific heat of a material, first look at the units. There is energy per unit mass per unit temperature. So if we are given an amount of energy appllied to an object, its mass and how much the temperature of the object rises, we can calculate its specifc heat by dividing the energy by both the mass and the temperature, but don't forget to keep the units as they are:
Specific heat of the metal = (95 cal)/(10 K * 700g) = 0.014 cal/(g*K)
To find how much energy it requires to melt 250 grams of ice, we will need what is called the Latent Heat of Melting for ice. This is the amount of heat required to change unit mass of a solid into unit mass of a liquid at a constant temperature. Again, using a reference, the latent heat of melting for ice is found to be 334 kJ/kg. So the energy required to melt one kg of ice is 334 kJ. The amount of energy required to melt 0.250 kg of ice is then:
334 * 0.250 = 83.5 kJ
The ratio of N₂ to hydrogen is 1:3
so if N₂ is 2 then hydrogen will be six
2:6.
6 moles
Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons containing carbon and hydrogen atoms. However, motor oil is much more viscous Motor Oil
A chef is using honey in a recipe. The honey is too thick to pour out of the jar. How could the chef make the honey easier to pour? heat it
Water’s molar mass is 18.01 g/mol. The molar mass of methanol is 32.01 g/mol. At room temperature, water is 64% more viscous than methanol. Which substance has the stronger intermolecular attraction? water
Answer:Nothing, the photon just bounces off the surface.
Explanation:
According to Albert Einstein, a photoelectron can only be emitted from a metal surface when the energy of the incident photon is greater than the work function of the metal.
In the scenario described in the question, the work function of the metal is greater than the energy of the photon. Hence, the photon just bounces off the metal surface without emitting any electron.
