Ask question

Ask question

All categories

2 years ago

12

A six-pack of soda costs $2.49, a 12-pack of soda costs $3.99, and a 24-pack of soda costs $5.49. Which pack has the lowest cost

per unit?

1 answer:

vagabundo [1.1K]2 years ago

4 0

The 24 pack. The 6 pack would be 41 cents per unit, the 12 would be 33, but the 24 would be 22.

You might be interested in

Len [333]

Add both pair of shoes together. Then take that total and multiply by7% or.07

7 0

2 years ago

Please help me ٩( ᐛ )و

kondaur [170]

Answer:

uhm i cant really see it

Step-by-step explanation:

3 0

3 years ago

Which statement is true about the expressions below?

Zielflug [23.3K]

Is there a attachment because I don’t see anything

7 0

2 years ago

Help me please. 30 points :)

Nataly [62]

$\frac{(5 \: - \: 8x)}{( \sqrt{5 \: - \: 8x} )} \: = \: \sqrt{5 \: - \: 8x}$
For the result to be Real,
$5 \: - \: 8x \: \geqslant \: 0$
$8x \: \leqslant \: 5$
$x \: \leqslant \: \frac{5}{8}$
$( \frac{(5 - 8x)}{( \sqrt{5 - 8x} )} ) \: \times \: (\frac{ \sqrt{5 - 8x} }{ \sqrt{5 - 8x} } ) \: = \: \frac{ {(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
Hence,
$\frac{{(5 \: - \: 8x)}^{ \frac{3}{2} } }{(5 \: - \: 8x)}$
is the required form.

3 0

3 years ago

Find the oth term of the geometric sequence 5,--25, 125,

Genrish500 [490]

Given the geometric progression below

$5,-25,125,\ldots$

The nth term of a geometric progression is given below

$T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}$

From the geometric progression, we can deduce the following

$\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}$

To find the value of r, we will take ratios of two consecutive terms

$\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}$

To find the 9th term of the geometric, we will have that;

$\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}$

Hence, the 9th term of the geometric progression is 1953125

8 0

9 months ago