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3 years ago

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An antelope moving with constant acceleration covers the distance 72.0 m between two points in time 7.10 s . Its speed as it pas

ses the second point is 16.0 m/s .
a. What is its speed at the first point?
b. What is the acceleration?

1 answer:

Studentka2010 [4]3 years ago

3 0

Answer:

a. 4.28 m/s

b. 1.65 m/s²

Explanation:

a.

Speed: This can be defined as the ratio of distance to time. The S.I unit of speed is m/s.

From newton's equation of motion,

S = (v+u)t/2 ............................... Equation 1

Where S = distance, u = initial speed, v = final speed, t = time.

Given: S = 72 m, v = 16.0 m/s, t = 7.10 s.

Substitute into equation 1

72 = (16+u)7.10/2

making u the subject of the equation,

7.1(16+u) = 72×2

113.6+7.1u = 144

7.1u = 144-113.6

7.1u = 30.4

u = 30.4/7.1

u = 4.28 m/s

Thus the speed at the first point = 4.28 m/s

b.

Acceleration: This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s²

a = (v-u)/t............................ Equation 2

Where a = acceleration.

Given: v = 16.0 m/s, u = 4.28 m/s, t = 7.10 s

Substitute into equation 2,

a = (16-4.28)/7.1

a = 11.72/7.10

a = 1.65 m/s²

Thus the acceleration = 1.65 m/s²

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