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Irina-Kira [14]
3 years ago
12

Write the answer to this question. Energy is measured in units called joules(J). Suppose a roller coaster car starts with 78,000

J of potential energy. In a few seconds, it converts two-thirds of this energy into kinetic energy. As it takes a curve, the car doubles its kinetic energy. How much mechanical energy does the car now have?
Physics
1 answer:
kolezko [41]3 years ago
7 0

Answer:78,000 J

Explanation:

Given

Initial Potential Energy P=78,000 J=78 kJ

Total Energy=Potential Energy+Kinetic Energy

initially kinetic energy is zero therefore

Total Energy=Potential Energy

If two-thirds of this energy converts to kinetic Energy

i.e. kinetic Energy =\frac{2}{3}\times 78=2\times 26=52 kJ

As it take curve its kinetic Energy doubles i.e.2\times 52=104 kJ

but total Energy is constant i.e. 78 kJ

therefore there must be a decrease in Potential energy of coaster

78=104+P.E.

P.E.=-26 kJ

Mechanical Energy of car is =sum of kinetic and Potential Energy

=78 kJ=78,000 J

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One student made the incomplete diagram shown below to represent the relationship between igneous rocks, sediments, sedimentary
Kryger [21]

Answer: Option (C)

Explanation: Rock cycle plays an important role in the alteration of rocks from one form to another.

  1. Igneous rocks when undergoes high temperature and pressure condition, it transforms into a metamorphic rock.
  2. Sedimentary rocks are formed from the sedimentation and consolidation of sediments
  3. Igneous rocks are formed due to the crystallization of magma.

Hence the correct answer is option (C)

3 0
4 years ago
The star Betelgeuse is 6.1 x 10^18 m away from Earth. How old is the light we see from that star when it reaches us? There are 3
castortr0y [4]

Answer:

635 years old

Explanation:

The light reaching the earth from the sun will travel at a speed called the speed of light, and this has a universal value of 3 × 10⁸ m/s. Bearing this in mind, let us calculate the age of the light reaching the Earth from the sun:

Distance of star from Earth = 6.1 × 10⁸m

Speed of light = 3 × 10⁸ m/s

We have distance and speed, let us calculate the time of travel of the light from the star to the earth.

Distance = speed × time

6.1 × 10⁸ = 3 × 10⁸ × time

time = \frac{6.1 \times 10^{18}}{3 \times 10^8}

In order to do the division above, we will divide the whole numbers normally, then we will apply the law of indices to the power that says:

Xᵃ ÷ Xᵇ = X⁽ᵃ⁻ᵇ⁾

\therefore time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\\= \frac{2.03 \times 10^{(18-8)}}{1} \\= 2.03 \times 10^{10}}\ seconds

Next, we are told that there are 3.2 × 10⁷ seconds in a year.

∴ The number of years travelled by the light from the star:

3.2\ \times 10^7\ seconds = 1\ year\\1\ second =  \frac{1}{3.2\ \times 10^7} \\\therefore 2.03 \times 10^{10}\ seconds = \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}

please note that:

2.03 × 10¹⁰ = 20300000000

3.2 × 10⁷ = 32000000

\therefore \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\\= \frac{20300000000}{32000000} \\\\= \frac{20300}{32} \\= 634.347\ years\\

The closest answer in the option is 635 years, and we are short of this by some points due probably to approximations in the calculation.

8 0
3 years ago
A couch of mass 210 kg is being pushed across the floor with an applied force of 4100 N. The coefficient of kinetic friction bet
Dennis_Churaev [7]
Let us use the formula for Newton's Second Law of Motion:

Net force = Mass*Acceleration
Net force = Applied Force - μ*Normal Force
where μ is the coefficient of kinetic friction

Normal Force = Force due to gravity = mass*gravity
Normal Force = (210 kg)(9.81 m/s²) =<em> 2,060.1 N</em>

Then,
Net force = 4100 - 0.38*2060.1 = 3317.162 N

3317.162 N = (210 kg)(a)
Solving for acceleration,
<em>a = 15.796 m/s²</em>
8 0
4 years ago
How are all paths that have a displacement of zero similar??
alex41 [277]
Displacement is known as the net movement of an object with respect to its original position. One may travel out of his city and return. Despite having covered many miles, he will have have a displacement of 0.
This is true for all paths that have zero displacement, that they all return to their original position.
6 0
3 years ago
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Does the diagram show a spring or neap tide?How do you know?
vampirchik [111]
It shows a neap tide 
6 0
4 years ago
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