1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
skad [1K]
3 years ago
15

Determine W (or fuel energy) required to launch a satellite of mass m at rest from a launching pad placed at the surface earth,

to a circular orbit where the radius of the orbit is r = 5 R where R is the radius of the earth. Ignore the effect of the Earth’s rotation. Take the mass of the Earth to be M. The fuel energy required is:_______.
1. 5GmM/ (4R)
2. 3GmM/(2R)
3. 7GmM/(6R)
4. 2GmM/R
5. 9GmM/(10R)
6. 5GmM/(6R)
7. 11GmM/(10R)
8. 3GmM/(4R)
Physics
1 answer:
jeka57 [31]3 years ago
7 0

Answer:

5. 9GmM/(10R)

Explanation:

m is the mass of the satellite

M is the mass of the earth

W is the energy required to launch the satellite

Energy at earth surface = Potential energy (PE) + W

W = Energy at earth surface - Potential energy (PE)

But PE = -\frac{GMm}{R}

Therefore: W = Energy at earth surface - \frac{GMm}{R}

Energy at earth surface (E) at an altitude of 5R = -\frac{GMm}{5r} +\frac{1}{2}mV^2

But V=\sqrt{\frac{GM}{5R} }

Therefore: E=-\frac{GMm}{5R}+\frac{1}{2}m(\sqrt{\frac{GM}{5R} } )^2=  -\frac{GMm}{5R}+\frac{GMm}{10R}  = -\frac{GMm}{10R}

W = E - PE

W=-\frac{GMm}{10R}-(-\frac{GMm}{R})=-\frac{GMm}{10R}+\frac{GMm}{R}=\frac{9GMm}{10R} \\W=\frac{9GMm}{10R}

You might be interested in
Due to historical difficulty in delivering supplies by plane, one of your colleagues has suggested you develop a catapult for sl
ikadub [295]

Answer:

Please see below as the answer is self-explanatory.

Explanation:

  • We can take the initial velocity vector, which magnitude is a given (67 m/s) and project it along two directions perpendicular each other, which we choose horizontal (coincident with x-axis, positive to the right), and vertical (coincident with y-axis, positive upward).
  • Both movements are independent each other, due to they are perpendicular.
  • In the horizontal direction, assuming no other forces acting, once launched, the supply must keep the speed constant.
  • Applying the definition of cosine of an angle, we can find the horizontal component of the initial velocity vector, as follows:

       v_{avgx} = v_{o}*cos 50 = 67 m/s * cos 50 = 43.1 m/s (1)

  • Applying the definition of average velocity, since we know the horizontal distance to the target, we can find the time needed to travel this distance, as follows:

       t = \frac{\Delta x}{v_{avgx} } = \frac{400m}{43.1m/s} = 9.3 s  (2)

  • In the vertical direction, once launched, the only influence on the supply is due to gravity, that accelerates it with a downward acceleration that we call g, which magnitude is 9.8 m/s2.
  • Since g is constant (close to the Earth's surface), we can use the following kinematic equation in order to find the vertical displacement at the same time t that we found above, as follows:

       \Delta y = v_{oy}  * t - \frac{1}{2} *g*t^{2} (3)

  • In this case, v₀y, is just the vertical component of the initial velocity, that we can find applying the definition of the sine of an angle, as follows:

       v_{oy} = v_{o}*sin 50 = 67 m/s * sin 50 = 51.3 m/s (4)

  • Replacing in (3) the values of t, g, and v₀y, we can find the vertical displacement at the time t, as follows:

       \Delta y = (53.1m/s * 9.3s) - \frac{1}{2} *9.8m/s2*(9.3s)^{2} = 53.5 m (5)

  • Since when the payload have traveled itself 400 m, it will be at a height of 53.5 m (higher than the target) we can conclude that the payload will be delivered safely to the drop site.
4 0
3 years ago
300,000,000m/s × 2 = —— m
nekit [7.7K]

Answer:

6 x 10⁸ m

Explanation:

300,000,000 m/s x 2 s

= 3 x 10⁸ x 2

= 6 x 10⁸ m

7 0
2 years ago
An element has 4 protons, 5 neutrons, and 4 electrons. What is the atomic mass of the element? 4 5 8 9
alex41 [277]

at mass = protons+neutrons=9

5 0
3 years ago
Read 2 more answers
You would like a pendulum that swings back and forth once every 2 seconds, but the one you have swings once every 1.9 seconds. W
patriot [66]

Your pendulum does a complete swing in 1.9 seconds.  You want to SLOW IT DOWN so it takes 2.0 seconds.

Longer pendulums swing slower.

You need to <em>make your pendulum slightly longer</em>.

If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom.  You can add weight or cut some off, and it won't change the speed a bit.  

6 0
3 years ago
Mass is 56.8 g and the volume is 10 mL what is the density
scoundrel [369]
Answer: 5.68g/ML.

Explanation; Divide the mass of the unknown substance and the volume of the unknown substance and you will have your answer.

Hope this helps! ^^ if you can pls mark me brainiest!
6 0
3 years ago
Other questions:
  • A small smooth object slides from rest down a smooth inclined plane inclined at 30 degrees to the horizontal. What is (i) the ac
    10·1 answer
  • Dams hold collected water back from flowing at their normal rate. What type of energy is in the collected water above the dam? c
    13·2 answers
  • Write the equation that links current, potential difference, and resistance
    13·1 answer
  • F the radius of a sphere is increasing at the constant rate of 2 cm/min, find the rate of change of its surface area when the ra
    11·1 answer
  • Corrosion is the tendency of a metal to revert back to its natural state.
    8·1 answer
  • A table exerts a 4.0 Newton force on a book which lies at rest on its top. The force exerted by the book on the table is
    15·2 answers
  • How do you find the molarity of: 48.2 g of sodium carbonate in 0.500 L of solution
    7·1 answer
  • QUICKK I NEED HELP!!<br> How is a mineral different from an element rock
    12·2 answers
  • Stars are held together by the force ___, ___ and the composition determine the amount of ___.
    7·1 answer
  • In the sum of 4.34 + 5.66, the number of significant figures is
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!