I think that when work is done and a force istransferred an object must move in the direction of the force.
F=ma so, do 3.80s x 59 KG which will give you your answer, hope this helps <3
Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"
Solution
part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude (

) of the orbit:

This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude,

. So we can write

where

is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:

part b) The orbit has a circumference of

, and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is

So, the period of the orbit is 2.45 hours.
Answer:
Explanation:
Average power per unit area =
I avg = c B₀² / 2μ₀
= 3 X 10⁸ X (3.2 X 10⁻⁷)² / 2 X 4π × 10⁻⁷
= 1.22 X 10
12 . 2 W / m²
Answer:
120 deg Unknown = 100 deg Celsius since we know that the ice point is at
0 deg Celsius and the steam point is 100 deg Celsius
So you have 1.2 deg U / 1 deg C
70 deg U / (1.2 deg U / 1 deg c) = 58.3 deg C (temperature in deg Celsius)
Or 58.3deg C * 1.2 deg U / 1 deg C = 70 deg U