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rosijanka [135]

3 years ago

10

When an inclined plane is used, A. the mechanical advantage increases as the height increases. B. a smaller force is exerted ove

r a longer distance. C. a negative mechanical advantage can result. D. a greater force is exerted over a shorter distance

1 answer:

lesantik [10]3 years ago

7 0

Choice-B says it all.

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MissTica

I think that when work is done and a force istransferred an object must move in the direction of the force.

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4 years ago

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Suppose the ring rotates once every 3.80 s . if a rider's mass is 59.0 kg , with how much force does the ring push on her at the

galina1969 [7]

F=ma so, do 3.80s x 59 KG which will give you your answer, hope this helps <3

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4 years ago

Whenever two apollo astronauts were on the surface of the moon, a third astronaut orbited the moon. assume the orbit to be circu

almond37 [142]

Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"

Solution

part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude ( $h=430 km=4.3 \cdot 10^5 m$ ) of the orbit:
$r= r_0 + h=1.7 \cdot 10^6 m + 4.3 \cdot 10^5 m=2.13 \cdot 10^6 m$
This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude, $g=1.08 m/s^2$ . So we can write
$g=a_c= \frac{v^2}{r}$
where $a_c$ is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:
$v= \sqrt{g r}= \sqrt{(1.08 m/s^2)(2.13 \cdot 10^6 m)}=1517 m/s = 1.52 km/s$

part b) The orbit has a circumference of $2 \pi r$ , and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is
$T= \frac{2 \pi r}{v} = \frac{2\pi (2.13 \cdot 10^6 m)}{1517 m/s} =8818 s = 2.45 h$
So, the period of the orbit is 2.45 hours.

6 0

3 years ago

An electromagnetic wave with a peak magnetic field component of 3.20 × 10−7 T carries what average power per unit area? (μ0 = 4π

IRISSAK [1]

Answer:

Explanation:

Average power per unit area =

I avg = c B₀² / 2μ₀

= 3 X 10⁸ X (3.2 X 10⁻⁷)² / 2 X 4π × 10⁻⁷

= 1.22 X 10

12 . 2 W / m²

4 0

3 years ago

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a mercury in glass thermometer reads -20° at the ice point and 100°at the steam point. calculate the Celsius temperature corresp

Anestetic [448]

Answer:

120 deg Unknown = 100 deg Celsius since we know that the ice point is at

0 deg Celsius and the steam point is 100 deg Celsius

So you have 1.2 deg U / 1 deg C

70 deg U / (1.2 deg U / 1 deg c) = 58.3 deg C (temperature in deg Celsius)

Or 58.3deg C * 1.2 deg U / 1 deg C = 70 deg U

4 0

3 years ago