Complete question :
A 12 m x 15 m house is built on a 12-cm-thick concrete slab.
What is the heat-loss rate through the slab if the ground temperature is 5°C while the interior of the house is 25°C
Answer:
3kW
Explanation:
Given the following :
Dimension of house :
Length = 12m
Width = 15m
Thickness of concrete slab (t) = 12cm
t in metres :
100cm = 1m
12cm = (12/100)m
= 0.12m
Ground temperature (Tg) = 5°C
Interior temperature = (Th) = 25°C
Thermal conductivity of concrete (K) is approximately 1 Wm/k
Using the relation:
Q = KA * [ (Th - Tg) / d]
A = Length * width = (12 *15) = 180
Q = (1 * 180) * [(25°C - 5°C) / 0.12]
Q = 180 * (20/0.12)
Q = 180 * 16.6666
Q = 3,000W = 3kW
Answer:
Centripetal acceleration will be equal to
Explanation:
We have given time taken to cover 180° is 0.5 sec
So time taken by 360° is equal to = 2×0.5 = 1 sec
Radius of the circle r = 0.520 m
So distance 
So velocity 
We have to find the centripetal acceleration
Centripetal acceleration will be equal to 
So centripetal acceleration will be equal to
Answer:
water, air, vegetation, and light. also a good temperature thats not too hot or too cold
Explanation:
Answer:
the work done by a person is 1,732 J
Explanation:
The computation of the work done by a person is as follows;
The following information is given
Force = 200.N
Distance = 10.0 meters
Angle = 30 degrees
based on the above information
Work done is

Work done is
= (200) (cos 30 degrees) (10.0 meters)
= 1,732 J
hence, the work done by a person is 1,732 J
The same is considered and relevant
If the force is removed, then there are no other forces acting on the object, the object will continue to move at constant velocity, meaning that it would move in a line tangent to the circular path.