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Veseljchak [2.6K]
2 years ago
12

Can anyone help me? I’ll give Brainly!!!

Mathematics
2 answers:
zlopas [31]2 years ago
5 0

Answer:

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

olya-2409 [2.1K]2 years ago
3 0

Answer:

Step-by-step explanation:

its 12 yd

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The weight of people in a small town in missouri is known to be normally distributed with a mean of 154 pounds and a standard de
ad-work [718]
If a random sample of 20 persons weighed 3,460, the sample mean x-bar would be 3460/20 = 173 pounds.
The z-score for 173 pounds is given by:
z=\frac{173-154}{29}=0.655
Referring to a standard normal distribution table, and using z = 0.66, we find:
P(\bar x\ \textless \ 173)=0.7454
Therefore
P(\bar x\ \textgreater \ 173)=1-0.7454=0.2546
The answer is: 0.2546

4 0
3 years ago
Calculate the area of quadrilateral ABCD.<br> State the units of your answer.
cluponka [151]

Answer:

158.76 cm²

Step-by-step explanation:

Quadrilateral ABCD is composed of 2 right triangles

Construct the line BD, then

Δ ABD and Δ BCD are the 2 right triangles.

The area (A) of a triangle is calculated using

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

Δ ABD with b = 18 and h = 7.5

A = \frac{1}{2} × 18 × 7.5 = 9 × 7.5 = 67.5 cm²

Δ BCD with b = 15.6 and h = 11.7

A = \frac{1}{2} × 15.6 × 11.7 = 7.8 × 11.7 = 91.26 cm²

Thus

area of ABCD = 67.5 + 91.26 = 158.76 cm²

3 0
3 years ago
How much heat is required to raise the temperature of
Elina [12.6K]

Answer:

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Step-by-step explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature = T_1 = 15°c

The final temperature = T_2  = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q =  m × s × ( T_2 - T_1 )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q =  50 g × 2260.0 J/g × 85°c

∴   Q = 9,605,000  joule

Or, Q =  9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer

4 0
2 years ago
State the dimensions of the matrix. identify the indicated element​
dalvyx [7]

Answer:

A

Step-by-step explanation:

In a matrix we go by row, then column so 2 rows and 3 columns

6 0
2 years ago
Two different linear functions are shown below with two points given from each function Use slope-intercept form Function A has
Dmitriy789 [7]

Answer:

This answer is option 1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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