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3 years ago

A fatty acid consists of -COOH bonded to a long chain of:

2 answers:

7 0

The -COOH is bonded to a long chain of hydrocarbons in a fatty acid.

A hydrocarbon chain is comprised of both carbon (C) and hydrogen (H) atoms. The 'acid' part is made up of the -COOH portion, whereas the 'fatty' part is made up of the long hydrocarbon chain that it is attached to.

sashaice [31]3 years ago

7 0

Answer: Option (1) is the correct answer.

Explanation:

A chain of carbon and hydrogen atoms also known as hydrocarbons when attached to at least one carboxylic acid functional group (COOH) then it is known as a fatty acid.

For example, $CH_{3}(CH_{2})_{10}COOH$ is lauric acid and it is a saturated fat.

Whereas a hydrocabon that contain atleast one "-OH" functional group is known as an alcohol.

A hydrocabon that contain atleast one "-CHO" functional group is known as an aldehyde.

A hydrocabons that contain atleast one "O=C-O" functional group is known as an ester.

Thus, we can conclude that a fatty acid consists of -COOH bonded to a long chain of hydrocarbons.

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Provide one example of how life on Earth would not be possible without water based on its characteristics.

snow_lady [41]

Answer: ice is less dense than liquid water. If ice was more dense, Earth would freeze.

Explanation: There are many reasons why life on Earth depends on the characteristics of water. One could discuss hydrogen bonds and its role as a solvent, but the unusual property of water is is the change in density with change in temperature. Water is densest at 4 degC, which is why ice floats - it is less dense than cold water (it melts quickly in warm water, so density isn’t impotant at higher temperatures). Most liquids are less dense than the solid, frozen form. If this was the case with water, any ice that formed would sink, and sease would freeze from the bottom up. Furthermore, the lowest layers would be insulated and would not all melt in summer. Thus over time, the seas would become a thin layer of liquid water at best, over solid ice. Life could not develop without liquid seas. In addition, ice is reflective, reducing the amount of sunlight absorbed, further reducing temperatures. Without ocean circulation, polar areas would be even colder, and there would be no rain.

6 0

3 years ago

I NEED HELP ASAP!!!!<br><br><br><br> ITS DUE IN A FEW MINUTES!!!!

OleMash [197]

Answer:

The Sun and the planets were born from a cloud of gas and dust called the solar nebula 4.6 billion years ago. The collapse of the solar nebula was most likely triggered by a shock wave from a nearby supernova explosion. The Sun formed in the center, with the planets surrounding it in a thin disk.

Explanation:

6 0

3 years ago

4. What is the total mass of ice that can be vaporized by 2100 kJ of heat energy?

anygoal [31]

Answer:

5 g

Explanation:

The heat required to vaporize ice is the sum of

i) Heat required to melt ice at 0°C

ii) Heat required to raise the temperature from 0°C to 100°C

iii) Heat required to vaporize water at 100°C

Thus;

H = nLfus + ncθ + nLvap

H= n(Lfus + cθ + Lvap)

Lfus = 6.01 kJ/mol

Lvap = 41 kJ/mol

c = 75.38

n =?

2100 = n(6.01 + 75.38(100) + 41)

n = 2100 KJ/7585.01 kJ/mol

n = 0.277 moles

Mass of water = number of moles * molar mass

Mass of water = 0.277 moles * 18 g/mol

Mass of water = 5 g

3 0

3 years ago

The table shows the thickness, top density, and bottom

OleMash [197]

$\huge{\textbf{\textsf{{\color{pink}{An}}{\red{sw}}{\orange{er}} {\color{yellow}{:}}}}}$

As depth increases, the density of the layers decreases.

Thanks.
Hope it helps.

3 0

3 years ago

Read 2 more answers

aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is

maksim [4K]

Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

4 0

3 years ago