Answer:
A. 1.50
Explanation:
9.01 x 1023 molecules* 1 mol/ 6.022×1023 molecules= 1.49618067087 moles
Rounded would be 1.50
Answer:
ACTIVATION OF PHOSPHORYLASE KINASE AND ALLOSTERICALLY ACTIVATION OF PHOSPHORYLASE KINASE B
Explanation:
In a contracting skeletal muscle, there is a rapid need of ATP by the muscle cell. The energy need is obtained by the degradation of glycogen into glucose which then enters glycolysis. Muscle contraction causes muscle depolarization in which there is the rapid influx of calcium ions from the sarcoplasmic reticulum into the sacroplasm of the myocytes. This in turn causes the binding of calcium ion with calmodulin which thenb activates phosphorylase kinase from which it allosterically activate the b form of the enzyme needed for the conversion of glycogen to glucose. The other options do not occur as a result of increase in cytolic calcium concentration.
Answer:
E. None of these
Explanation:
We know, By GAS laws,
PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature
Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.
= 
where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C
We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)
So putting values, we get

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

∴ V2 = 
∴ V2 = 20mL
Answer:
10
Explanation:
pH is defined as the negative logarithm of the concentration of hydrogen ions.
Thus,
pH = - log [H⁺]
Thus, from the formula, more the concentration of the hydrogen ions or more the acidic the solution is, the less is the pH value of the solution.
Thus, solution with pH = 3 will be more acidic than solution with pH =4
Thus, concentration of the [H⁺] when pH =3
3 = - log [H⁺]
[H⁺] = 10⁻³ M
For pH = 4, [H⁺] = 10⁻⁴ M
<u>hence, pH = 3 is 10 times more acidic than pH = 4</u>