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3 years ago

8

Latoya has 75fewer cards than Andrew. Clinton has 38 more cards than Latoya.clinton has 200 cards. How many picture cards does A

ndrew have?

1 answer:

Lena [83]3 years ago

7 0

L = A - 75
C = L + 38
C = 200

200 = L + 38
200 - 38 = L
162 = L

L = A - 75
162 = A - 75
162 + 75 = A
237 = A <====

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3 1/2 + 2 5/6 show me the work please

Zolol [24]

3 1/4 + 2 1/3
= 6712
= 5712≅ 5.583333
this example do it using this example

8 0

4 years ago

Solve for X. x-9+2wx=y

iragen [17]

Answer:

x=(y+9)/(1+2w)

Step-by-step explanation:

x-9+2wx=y

We make x the subject

x+2wx=y+9

x(1+2w)=y+9

Divide both sides by (1+2w)

x(1+2w)/(1+2w)=y+9(1+2w)

x=(y+9)/(1+2w)

5 0

3 years ago

Can someone help me!<br> if something cost $4.90 due to a 14% discount what is the original price

Vlad [161]

Answer:

$4.21

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 4.9 × 14/100

Discount = 4.9 x 0.14

You save = $0.69

Final Price = Original Price - Discount

Final Price = 4.9 - 0.686

Final Price = $4.21

6 0

3 years ago

Read 2 more answers

What is 7/10+1/4 in simplest form

Stells [14]

Answer: 19/20

Step-by-step explanation:

7/10 turns into 14/20

1/4 turns into 5/20

14/20 + 5/20

14 + 5 over 20

= 19/20

19/20 is in simplest form.

3 0

4 years ago

Read 2 more answers

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

5 0

3 years ago