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3 years ago

List two sources within a medical record where the information about present or recent illnesses is most likely to be found.

1 answer:

8 0

The two sources within a medical record where the information about present or recent illnesses is most likely to be found are the lab reports and the physician's order. The medical history and physical examination sections of the medical record should contain information about present illnesses. Other possible sources of information are patient referral letters, the discharge summary, and the operative report.

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Looking at this barometer is the air pressure high or low? What type of weather would you expect?

igomit [66]

Answer:

i think ti would be D. sorry if it's wrong.

Explanation:

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What surrounds all cells

erik [133]

The Cell membrane surrounds all living cells and is the most important organelle, there is also a similar plasma membrane that surrounds all the organelles except for the ribosome. It is composed of phospholipids, proteins, and carbohydrates, which are arranged in a fluid mosaic structure.

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small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi

irina [24]

Answer:

Frequency of p $= 0.684$

Frequency of p $= 0.316$

Number of individuals with homozygous dominant (AA) $= 47$

Number of individuals with heterozygous (Aa) $= 43$

Number of individuals with homozygous recessive (aa) $= 10$

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals $(q^{2})$ is $\frac{10}{100} = 0.1$

Now, q will be

$= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316$

As per Hardy Weinberg's equation -

$p + q = 1$

Substituting the value of q in above equation, we get -

$p + 0.316 = 1p = 1 -0.316\\p = 0.684$

Now the frequency of homozygous dominant (AA) will be

$p^{2} = 0.684^{2} \\= 0.467$

Hence, out of 100 people $0.467 * 100 = 46.7 or 47$ people are homozygous dominant (AA)

Like wise out of 100 people $0.1 * 100 = 10$ people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

$p^{2} + q^{2} + 2pq = 1\\$

Substituting the values in above equation, we get -

$0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433$

So, out of 100 people $0.433 * 100 = 43.3 or 43$ people are heterozygous (Aa)

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3 years ago

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mestny [16]

Answer:

I'm pretty sure the answer is A

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3 years ago

Autoregulation refers to

makkiz [27]

Answer:

Explanation:

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3 years ago