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podryga [215]
3 years ago
12

What's the greatest number for 5,3,1,4,7

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

5 3 1 2 7

Step-by-step explanation:


Black_prince [1.1K]3 years ago
6 0
75431
Hope it helps you
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How do i do this?!?! its due tomorrow helpppppp
3241004551 [841]

Consider for each point how far it is above (or below) the horizontal line y=2. Then plot its image the same distance below (or above) that line.

6 0
3 years ago
A researcher wishes to estimate the proportion of adults who have​ high-speed Internet access. What size sample should be obtain
slega [8]

Answer: 8359

Step-by-step explanation:

The formula for sample size needed for interval estimate of population proportion :-

n=p(1-p)(\frac{z_{\alpha/2}}{E})^2

Given : The significance level : \alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=z_{0.025}=\pm1.96

Previous estimate of proportion : p=0.32

Margin of error : E=0.01

Now, the required sample size will be :-

n=0.32(1-0.32)(\frac{1.96}{0.01})^2=8359.3216\approx8359

Hence, the required sample size = 8359

5 0
3 years ago
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Shtirlitz [24]
It’s a diagram ur welcome
3 0
3 years ago
Find the slope of (-2,1),(-2,2)
Natalija [7]

Answer:

there is no slope its undefined

Step-by-step explanation:

4 0
3 years ago
Prove that sin^4x + cos^4x= sinxcosx
yKpoI14uk [10]

Answer:

(the relation you wrote is not correct, there may be something missing, so I will simplify the initial expression)

Here we have the equation:

sin^4(x) + cos^4(x)

We can rewrite this as:

(sin^2(x))^2 + (cos^2(x))^2

Now we can add and subtract cos^2(x)*sin^2(x) to get:

(sin^2(x))^2 + (cos^2(x))^2 + 2*cos^2(x)*sin^2(x) - 2*cos^2(x)*sin^2(x)

We can complete squares to get:

(cos^2(x) + sin^2(x))^2 - 2*cos(x)^2*sin(x)^2

and we know that:

cos^2(x) + sin^2(x) = 1

then:

1 - 2*sin(x)^2*cos(x)^2

This is the closest expression to what you wrote.

We also know that:

sin(x)*cos(x) = (1/2)*sin(2*x)

If we replace that, we get:

1 - \frac{sin^2(2*x)}{2}

Then the simplification is:

cos^4(x) + sin^4(x)  = 1 - \frac{sin^2(2*x)}{2}

7 0
3 years ago
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