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JulsSmile [24]
3 years ago
7

At the beginning of a bobsled race, teammates push their bobsled along the track before jumping

Physics
1 answer:
JulijaS [17]3 years ago
3 0

KE=1/2mv^2

1/2(100)6^2

1800 J

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Calculate the mass of the earth if the radius of the earth is 6.38 × 10^6​
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Answer:

C

Explanation:

C is i thing

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3 years ago
A stun gun or TASER is designed to put out a few seconds worth of electric pulses that impress a
iren [92.7K]

Answer:

Resistance = 400000 Ohms

Explanation:

Given the following data;

Voltage = 1200 V

Current = 3 mA = 3/1000 = 0.003 A

To find the resistance;

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Resistance = 1200/0.003

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A space explorer is moving through space far from any planet or star. He notices a large rock, taken as a specimen from an alien
yaroslaw [1]
He should push it gently.
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3 0
4 years ago
A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.
JulsSmile [24]

Answer:

\mu =0.75

Explanation:

<u>Frictional Force </u>

When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:

F_c=m.a_c

The centripetal acceleration a_c is computed as

\displaystyle a_c=\frac{v^2}{r}

Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one

F_c=m.\frac{v^2}{r}

For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as

F_r=\mu N

The normal force N is equal to the weight of the car, thus

F_r=\mu .m.g

Equating both forces

\displaystyle \mu .m.g=m.\frac{v^2}{r}

Simplifying

\displaystyle \mu =\frac{v^2}{rg}

Substituting the values

\displaystyle \mu =\frac{19^2}{(49)(9.8)}

\boxed{\mu =0.75}

7 0
4 years ago
What does 'change only one variable at a time' mean
matrenka [14]

Answer: to only change one factor in an experiment or test

8 0
3 years ago
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