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3 years ago

10

Am I right? be honest

1 answer:

Bas_tet [7]3 years ago

5 0

Answer:

I chose c because it is the greater slope at point c

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Oil at 150 C flows slowly through a long, thin-walled pipe of 30-mm inner diameter. The pipe is suspended in a room for which th

chubhunter [2.5K]

Answer:

<em>1.01 W/m</em>

Explanation:

diameter of the pipe d = 30 mm = 0.03 m

radius of the pipe r = d/2 = 0.015 m

external air temperature Ta = 20 °C

temperature of pipe wall Tw = 150 °C

convection coefficient at outer tube surface h = 11 W/m^2-K

From the above,<em> we assumed that the pipe wall and the oil are in thermal equilibrium</em>.

area of the pipe per unit length A = $\pi r ^{2}$ = $7.069*10^{-4}$ m^2/m

convectional heat loss Q = Ah(Tw - Ta)

Q = 7.069 x 10^-4 x 11 x (150 - 20)

Q = 7.069 x 10^-4 x 11 x 130 = <em>1.01 W/m</em>

4 0

4 years ago

Match the nitrogenous base of RNA with its complement. TTACCGG TAACGCA CGCATGT TGACCTA GCCAATT ACTGGAT arrowRight GCGTACA arrowR

egoroff_w [7]

I took the test and this is the answer key showing I got it right..

Hope this helps!

3 0

3 years ago

Read 3 more answers

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

BartSMP [9]

Answer:

The value of g in Kepler-12b is $3.85 m/s^{2}$

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

$W = m.g$ (1)

Where m is the mass and g is the value of the gravity

$F = G \frac{M.m}{R^{2}}$ (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

$m.g = G \frac{M.m}{R^{2}}$ (3)

Then g will be isolated from equation 3:

$g = G \frac{M.m}{m.R^{2}}$

$g = \frac{G.M}{R^{2}}$ (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

$d = 2R$ (5)

Where d and R are the diameter and radius of Jupiter

$d_{jupiter} = 2(69911000 m)$

$d_{jupiter} = 139822000 m$

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

$d_{Kepler-12b} = 1.7(d_{jupiter})$

$d_{Kepler-12b} = 1.7(139822000 m)$

$d_{Kepler-12b} = 237697400 m$

By means of equation 5 the radius of Kepler-12b can be known:

$R_{Kepler-12b} = \frac{d}{2}$

$R_{Kepler-12b} = \frac{237697400 m}{2}$

$R_{Kepler-12b} = 118848700 m$

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of $1.898x10^{27}$ kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

$m_{Kepler-12b} = 0.43(m_{jupiter})$

$m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)$

$m_{Kepler-12b} = 8.161x10^{26} Kg$

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

$g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}$

$g = 3.85 m/s^{2}$

Hence, in Kepler-12b the gravity has a value of $3.85 m/s^{2}$

8 0

3 years ago

You are using an 8 th order low-pass filter. Determine the roll-off achievable in the stop band, in dB/dec, and determine the ph

Andreas93 [3]

Answer: The complexity of filter is the order of the filter. Greater the order of the filter, more efficient the filter is. Roll of value of one filter is 20dB/dec. So the roll-off value of 8th order filter is 160dB/dec. 8th order filter is more efficient than the second order low-pass filter.

4 0

3 years ago

A body is projected vertically upwards with a velocity of 10m/s from a vertically upward position at height h another body is dr

RoseWind [281]

Answer:

0.25 second

Explanation:

Given :

Velocity, v = 10 m/s

The height,

$h = \frac{v^2}{2g}$

$h = \frac{10^2}{2\times 9.8}$

= 5 m

Therefore the time at which both the bodies meet is

$t = \frac{h}{v+v}$

$t = \frac{5}{10+10}$

$t = \frac{5}{20} = 0.25$

So, time taken is 0.25 seconds

3 0

3 years ago