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Molodets [167]
2 years ago
11

How much energy is created when there is 110 W of power over 30s?

Physics
1 answer:
Makovka662 [10]2 years ago
5 0

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

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Maybe nobody ever mentioned it to you, but it turns out that
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<span>==>  The total current is just the amount of current
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and out of </span><span>the battery.

Diagram #1).
</span>The total current coming out of the battery is 15 A.
That current is going to split up when it reaches the resistors.
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Diagram #2).
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That current is going to split up when it reaches the resistors.
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8 0
3 years ago
A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rat
just olya [345]

Answer:

1.dr/dt=0.0096cm/s

2. dA/dt=2.19cm^2/s

Explanation:

A spherical balloon is deflating at 10 cm3/s. At what rate is the radius changing when the volume is 1000π cm3 ? What is the rate of change of surface area at this moment?

for this question, we need to analyze the parameters we know

V=volume of the spherical balloon 1000π cm3

volume of the sphere=\frac{4}{3} \pi r^{3}

1000π=4/3πr^3

dividing both sides by 4

250*3=r^3

r=9.08cm, the radius of the balloon

dv/dt=dv/dr*dr/dt...................................1

dv/dr  ,means

V=\frac{4}{3} \pi r^{3}

dv/dr=4*pi*r^2

dv/dt=10 cm3/s

from equ 1

10=4*pi*9.08^2*dr/dt

10=1036 dr/dt

dr/dt=10/1036

dr/dt=0.0096cm/s

2. to find the rate at which the area is changing we have,

dA/dt=dA/dr*dr/dt

area of a sphere is  4πr^2

differentiate a with respect to r, radius

dA/dr=8πr

dA/dt=8πr*0.0096

dA/dt=8*pi*9.08*0.0096

dA/dt=2.19cm^2/s

is the rate of change of the surface area

7 0
3 years ago
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