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2 years ago

11

How much energy is created when there is 110 W of power over 30s?

1 answer:

Makovka662 [10]2 years ago

5 0

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

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What is an example of a stable system

oksian1 [2.3K]

Some examples of stable system are:

1) functions of sine

2) DC

3) signum

4) unit step

5) cosine.

Happy Studying! ^^

6 0

3 years ago

Read 2 more answers

Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up

kirza4 [7]

Answer:

I believe the answer is b

Explanation:

5 0

4 years ago

A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete

Lesechka [4]

Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is $6.25\times 10^{- 3} ft/s^{2}$

Solution:

As per the question:

Constant velocity of the horse in the horizontal, $v_{x} = 1 ft/s$

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

$20^{2} + 10^{2} = l^{2}$

$l^{2}= 500$

Now,

$x^{2} + y^{2} = 500$ (1)

Differentiating equation (1) w.r.t 't':

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$

$x\frac{dx}{dt} = - y\frac{dy}{dt}$

where

$\frac{dx}{dt}$ = Rate of change of displacement along the horizontal

$\frac{dy}{dt}$ = Rate of change of displacement along the vertical

$v_{x}$ = velocity along the x-axis.

$v_{y}$ = velocity along the y-axis

$xv_{x} = -yv_{y}$

$v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s$

$|v_{y}| = 0.5\ ft/s$

Acceleration of the hay bale is given by the kinematic equation:

$v_{y}^{2} = u_{y} + 2ay$

$(-0.5)^{2} =0 + 2ay$

$0.25 = 2ay$

$\frac{0.25}{2y} = a$

$a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}$

7 0

3 years ago

Suppose that a constant force is applied to an object with a mass of 12kg, it’s creates an acceleration of 5m/s^2. The accelerat

Klio2033 [76]

Answer:

Mass of second object will be 15 kg

Explanation:

We have given mass of first object = 12 kg

Acceleration $a=5m/sec^2$

According to second law of motion we know that force F = MA

So force $F=12\times 5=60N$

As the same force is applied to the second object of acceleration $a=4m/Sec^2$

So force = ma

$60=m\times 4$

m = 15 kg

So mass of second object will be 15 kg

5 0

3 years ago

Help me plzzz?? I need help it on the picture

madam [21]

No.
The acceleration of gravity on or near Earth's surface is 9.8 m/s² ,
not 20 m/s² .

If it were 20 m/s², then you would weigh almost exactly double
what you really weigh now.

3 0

3 years ago