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2 years ago

What is the motion of the particles in this kind of wave?

Physics

1 answer:

densk [106]2 years ago

8 0

The particles will move up and down over small areas.

Option B.

<u>Explanation:</u>

The type of the wave that has been discussed in the question is the transverse kind of wave. The transverse kind of wave are the waves where the particle motion is the perpendicular to the motion of the wave.

In the transverse kind of wave the which is a moving kind of a wave where the oscillations are perpendicular to the direction of the movement of the wave.

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3 years ago

Why are chemical properties harder to observe than physical properties?

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2 years ago

The atmosphere is held together by

Vera_Pavlovna [14]

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3 years ago

The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o

LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

$\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})$ (1)

Where:

$\bar F$ - Average impact force, in newtons.

$\Delta t$ - Duration of the impact, in seconds.

$m$ - Mass of the sledge hammer, in kilograms.

$v_{1}$ , $v_{2}$ - Initial and final velocity, in meters per second.

If we know that $\Delta t = 0.0020\,s$ , $m = 4\,kg$ , $v_{1} = -6\,\frac{m}{s}$ and $v_{2} = 0\,\frac{m}{s}$ , then we estimate the average impact force is:

$\bar F = \frac{m\cdot (v_{2}-v_{1})}{\Delta t}$

$\bar F = 12000\,N$

The average impact force is 12000 newtons.

5 0

3 years ago