What is the motion of the particles in this kind of wave?
1 answer:
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Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation () to find v final, or the v to the left of the equal sign. We know
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of and do the same to the right side of the equation. Therefore, we can find v final with:
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get:
The final answer is 236.057 m/s.
To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.
Here,
h = Depth average
= Density
Moreover,
Replacing,
Finally the force