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nirvana33 [79]
3 years ago
7

What is true about empirical and molecular formulas?

Physics
1 answer:
lora16 [44]3 years ago
7 0

Answer:

Molecular formulas explains how many atoms of each element are in a compound, and empirical formulas explains the simplest or reduced ratio of elements in a compound. For instance, If a compound's molecular formula cannot be further reduced any more, then the empirical formula is the same as the molecular formula.

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A metal disk of radius 4.0 cm is mounted on a frictionless axle. Current can flow through the axle out along the disk, to a slid
TiliK225 [7]

Answer:

Friction force is 0.1375 N

Solution:

As per the question:

Radius of the metal disc, R = 4.0 cm = 0.04 m

Magnetic field, B = 1.25 T

Current, I = 5.5 A

Force on a current carrying conductor in a magnetic field is given by considering it on a differential element:

dF = IB\times dR

Integrating the above eqn:

\int dF = IB\int_{0}^{R}dr

\tau = IB\times \frac{R^{2}}{2} = \frac{1}{2}IBR^{2}          (1)

Now the torque is given by:

\tau = F\times R                        (2)

From eqn (1) and (2):

F\times R = \frac{1}{2}IBR^{2}

Thus the Frictional force is given by:

F = \frac{1}{2}\times 5.5\times 1.25\times 0.04 = 0.1375\ N

5 0
3 years ago
A ball of mass 500g is thrown upwards with a velocity of 15m/s. Calculate its momentum at the highest point.
snow_tiger [21]

Answer:

zero

Explanation:

7 0
3 years ago
What is the answer to this question?
sesenic [268]

Answer:                Unknown

Explanation:         ???

8 0
3 years ago
The figure below shows a dipole. If the positive particle has a charge of 37.3 mC and the particles are 3.08 mm apart, what is t
kolbaska11 [484]

The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

<h3>Electric field of the positive particle</h3>

The electric field is calculated as follows;

E = kq/r²

where;

  • r is the distance between the charges
  • k is Coulomb's constant
  • q is magnitude of the charge

midpoint of 3.08 m, x = 1.54 mm

r(1.54 mm, 2.00 mm)

|r| = √(1.54² + 2²)

|r| = 2.52 mm

E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²

E = 5.287 X 10¹³ N/C

Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

5 0
2 years ago
Which tools would sara us to find an irregularly shaped objects mass and volume A. a meter stick , a ruler , and water
tester [92]
I think it's D. Usually, to find the volume of an irregularly shaped object, you put it in water with a labeled beaker to measure how much the water rises. The balance would be used to measure the mass in grams.
4 0
3 years ago
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