2x-5=95 due to the alternate interior angles thm so you just add 5 to 95 to get 2x=100 then divide by 2 to get x=50!
<h2>
Hello!</h2>
The answer is:
The area of this figure is 946 square inches.
<h2>
Why?</h2>
We can see that the figure is composed by two rectangles with diferrent dimensions, so, to calculate the area of the entire figure.
So,
For the first rectangle, we have:

The area will be:

For the second rectangle, we have:

The area will be:

Now, calculating the area of the entire figure, we have:

Have a nice day!
Answer:
3802 8/9
Step-by-step explanation:
So what you do is you make 52 1/3 and 72 2/3 improper fractions like 157/3 and 218/3. Then you multiply and get 34218/9. Then you simplafiy and get 3802 8/9
(a) True. Suppose A is a not a square matrix, with m rows and n columns. Then A² is not defined, because you can't multiply an m×n matrix by another m×n matrix.
(b) False. As an example, consider the matrices


Then both AB and BA are defined, with


In general, you can multiply any m×n by any n×m matrix.
(c) True. Multiplying a m×n matrix by a n×m matrix always yields a m×m matrix, and multiplying a n×m matrix by a m×n matrix always yields a n×n matrix.