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3 years ago

The box plots below show student grades on the most recent exam compared to overall grades in the class:

Mathematics

2 answers:

svetlana [45]3 years ago

7 0

<span>he box plots below show attendance at a local movie theater and high school basketball games: two box plots shown. The top one is labeled Movies. Minimum at 60, Q1 at 65, median at 95, Q3 at 125, maximum at 150. The bottom box plot is labeled Basketball games. Minimum at 90, Q1 at 95, median at 125, Q3 at 145, maximum at 150. Which of the following best describes how to measure the spread of the data? The IQR is a better measure of spread for movies than it is for basketball games. The standard deviation is a better measure of spread for movies than it is for basketball games. The IQR is the best measurement of spread for games and movies. The standard deviation is the best measurement of spread for games and movies.</span>

Gennadij [26K]3 years ago

4 0

Answer:

The answer is The additional scores in the second quartile for the exam data make the median higher.

Step-by-step explanation:

I just took the test

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The answer is x = 3.

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3 years ago

23.A chef ordered 400 pounds of potatoes in same-sized bags. Which expressions show

mrs_skeptik [129]

Answer:

10*40

80*5

20*20

Step-by-step explanation:

20*20=400

80*5=400

10*40=400

5 0

4 years ago

An adult ticket to a museum costs $3.00 more than a children's ticket. When 200 adult tickets and 100 children's tickets are sol

devlian [24]

7.50 is the cost of the childrens tickets hope that answer helps!

4 0

3 years ago

given the weekly demand curve of a local wine producer is p= 50-0.1q, and that the total cost function is c= 1500+ 10q, where q

ipn [44]

Answer:

a)the weekly profit as a function of price is $P=-10 p^2 + 600 p - 6500$

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

Step-by-step explanation:

The weekly demand curve of a local wine producer is p= 50-0.1q

p = price

q = quantity

Revenue function R =Price \times Quantity

R=(50-0.1q)q

$R=50q-0.1q^2$

Cost function: c= 1500+ 10q

Profit function=R(x)-C(x)

Profit function= $50q-0.1q^2-1500-10q$

Profit function= $40q-0.1q^2-1500$ ----1

We have q = 500 - 10 p using p = 50 − 0.1q

$P=-0.1 (500 - 10 p)^2 + 40 (500 - 10 p)- 1500\\P= -10 p^2 + 600 p - 6500$

General quadratic equation: $ax^2+bx+c=0$

On comparing

a = -0.1 , b = 40 , c = -1500

Maximum Profit is at q = $\frac{-b}{2a}=\frac{-40}{2(-0.1)}=200$

To find price must a bottle of wine be sold to realise maximum profit

p= 50-0.1q

p= 50-0.1(200)=30

Substitute the value of q in profit function(1) get the maximum profit

So, Profit function= $40\left(200\right)-0.1\left(200\right)^{2}-1500=2500$

Hence

a)the weekly profit as a function of price is $P=-10 p^2 + 600 p - 6500$

b) a bottle of wine be sold at $30 to realise maximum profit

c) the maximum profit that can be made by the producer is $2500

8 0

3 years ago

Please no link! need question answered as soon as possible

ira [324]

$\huge\bold{Given :}$

Angle 1 = 40°

Angle 2 = x°

Angle 3 = ( x + 28 )°

$\huge\bold{To\:find :}$

The value of x.

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

${\boxed{\mathcal{\purple{The\:value\:of\: x \:is\:56 ° .\:}}}}$ ✅

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

We know that,

$\sf\pink{Sum\:of\:angles\:of\:a\:triangle\:=\:180°}$

➪ ∠ 1 + ∠ 2 + ∠ 3 = 180°

➪ 40 + x° + x° + 28° = 180°

➪ 2x° + 68° = 180°

➪ 2x° = 180° - 68°

➪ x° = $\frac{112° }{2}$

➪ x° = 56°

$\sf\red{Therefore, \:the\: value \:of \:x\: is \:56°.}$

$\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}$

∠ 1 + ∠ 2 + ∠ 3 = 180°

✒ 40° + 56° + 56° + 28° = 180°

✒ 180° = 180°

✒ L. H. S. = R. H. S.

$\boxed{Hence\:verified.}$

$\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆$

3 0

3 years ago