Answer: You can say that the slope is negative since the graph is decreasing.
Step-by-step explanation:
![\bf f(x)=(x-6)e^{-3x}\\\\ -----------------------------\\\\ \cfrac{dy}{dx}=1\cdot e^{-3x}+(x-6)-3e^{-3x}\implies \cfrac{dy}{dx}=e^{-3x}[1-3(x-6)] \\\\\\ \cfrac{dy}{dx}=e^{-3x}(19-3x)\implies \cfrac{dy}{dx}=\cfrac{19-3x}{e^{3x}}](https://tex.z-dn.net/?f=%5Cbf%20f%28x%29%3D%28x-6%29e%5E%7B-3x%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3D1%5Ccdot%20e%5E%7B-3x%7D%2B%28x-6%29-3e%5E%7B-3x%7D%5Cimplies%20%5Ccfrac%7Bdy%7D%7Bdx%7D%3De%5E%7B-3x%7D%5B1-3%28x-6%29%5D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7Bdy%7D%7Bdx%7D%3De%5E%7B-3x%7D%2819-3x%29%5Cimplies%20%5Ccfrac%7Bdy%7D%7Bdx%7D%3D%5Ccfrac%7B19-3x%7D%7Be%5E%7B3x%7D%7D)
set the derivative to 0, solve for "x" to get any critical points
keep in mind, setting the denominator to 0, also gives us critical points, however, in this case, the denominator will never be 0, so... no critical points from there
there's only 1 critical point anyway, and do a first-derivative test on it, check a number before it and after it, to see what sign the derivative has, and thus, whether the graph is going up or down, to check for any extrema
Out of the 6 answers you have, the correct answers are 1, 3, 4, and 6.
Part A:
Function A:
Slope = (7-3)/(5-3) = 4/2 = 2
Equation:
y - 3 = 2(x - 3)
y - 3 = 2x - 6
y = 2x - 3
Funcion B:
(0, 3 ) and (-5, 0)
Slope = (3 - 0)/(0 + 5) = 3/5
y-intercept (0,3) so b = 3
Equation:
y = 3/5 x + 3
Function C:
y = 3x + 1
Part B:
Rate of change is the change in y over the change in x (rise/run). It's also the slope
Function A: rate of change = 2
Function B: rate of change = 3/5 (smallest)
Function C: rate of change = 3 (largest)
Order linear functions based on rate of change from least to greatest.
Function B: y = 3/5 x + 3
Function A: y = 2x - 3
Function C: y = 3x + 1
Answer:
a. 9 b.36 c. 100 d. 13689
