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2 years ago

Atoms of different elements have a different mass and volume. Why is the statement true?

1 answer:

6 0

Answer:different elements have different number of electrons and shells/orbits thatswhy it have different atomic mass and size.

Explanation:

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In this stoichiometry problem, determine the limiting reactant.

Tanya [424]

Answer:

Limiting reactant is NiSO₄

Explanation:

The reaction of aluminum metal with aqueous nickel(II) sulfate to produce aqueous aluminum sulfate and nickel is:

2 Al(s) + 3 NiSO₄ → Al₂(SO₄)₃ + 3 Ni

That means 2 moles of Al react with 3 moles of nickel sulfate.

Moles of Al and NiSO₄ are:

Al: 108g × (1mol / 26.98g) = 4.00 moles of Al

NiSO₄: 464g × (1mol / 154.75g) = 3.00 moles of NiSO₄

For a complete reaction of aluminium there are necessary:

4.00mol Al ₓ ( 3 moles NiSO₄ / 2 moles Al) = 6 moles of NiSO₄

As you have just 3.00 moles of NiSO₄, the limiting reactant is NiSO₄

8 0

2 years ago

Pls help

Dmitry_Shevchenko [17]

Answer:

The answer would be beryllium

You were probably confused but the correct answer would actually be a beryllium ion.

4 0

2 years ago

Which pair of elements is most apt to form an ionic compound with each other?

sweet [91]

Ionic compounds are compounds that are formed together by a cation and an anion. A cation is an ion with a positive charge. For example, Na+ and Ca2+. An ion has a negative charge, like Cl- and OH-. There is a greater chance of forming an ionic compound when they have a great difference in electronegativity, the ability to attract electrons toward itself. In the periodic table, elements that are opposite to each other, more likely found in opposite sides, would be more apt to form an ionic compound. Example would be NaCl and CaCl2 or Ca(OH)2.

7 0

2 years ago

A pH of 2 indicates a(n) _____.

solniwko [45]

A pH of 2 indicates a acid

6 0

3 years ago

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

Answer: The amount of barium sulfate produced in the given reaction is 0.667 grams.

Explanation:

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

3 years ago