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Burka [1]
3 years ago
10

HELLLPPPPP

Chemistry
2 answers:
Zepler [3.9K]3 years ago
6 0

Answer:

<h3><u><em>its A.</em></u></h3>

Explanation:

edge food and nutrition!!

zhannawk [14.2K]3 years ago
4 0

Answer:

whats the question

i dont get it where is the questionnnn

Explanation:

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why is a molecule of CO2 non polar even though the bonds between the carbon atom and the oxygen atoms are polar
stira [4]

Answer:

m

Explanation:

m

5 0
3 years ago
Plz help!!!!!!!!!!!!!!
Karo-lina-s [1.5K]
I think it’s d
If it’s wrong then I’m sorry
5 0
3 years ago
Read 2 more answers
At standard ambient temperature and pressure (SATP), a gas has density of 1.5328g/L. What is the molar mass of the gas?
ahrayia [7]

The standard ambient temperature and pressure are

Temperature =298 K

Pressure = 1atm

The density of gas is 1.5328 g/L

density = mass of gas per unit volume

the ideal gas equation is

PV = nRT

P = pressure = 1 atm

V = volume

n = moles

R= gas constant = 0.0821 Latm/mol K

T = 298 K

moles = mass / molar mass

so we can write

n/V = density / molar mass

Putting values

Pressure=\frac{nRT}{V}=\frac{massXRT}{VXmolarmass}

Pressure=\frac{densityXRT}{molarmass}

molarmass=\frac{densityXRT}{Pressure}=\frac{1.5328X0.0821X298}{1}=37.50

Thus molar mass of gas is 37.50g/mol

6 0
4 years ago
How many molecules of fructose would you have if you have 0.7 moles of<br> fructose?<br> *
iogann1982 [59]

Answer:

4.214 × 10^23 molecules.

Explanation:

Number of molecules in a substance can be calculated by multiplying the number of moles in that substance by Avagadro's number, which is 6.02 × 10^23.

That is, no. of molecule = n × Avagadro constant

In this case, there are 0.7 moles of fructose. Hence;

number of molecules = 0.7 × 6.02 × 10^23

no. of molecule = 4.214 × 10^23 molecules.

5 0
3 years ago
When 0.230 g of sodium metal is added to an excess of hydrochloric acid, 2390 J of heat are produced. What is the enthalpy of th
Dmitriy789 [7]

Answer:

ΔHrxn = 239 kj/mol

Explanation:

Given data:

Mass of sodium = 0.230 g

Heat produced = 2390 J

Solution:

Chemical equation:

2Na + 2HCl → 2NaCl + H₂

Number of moles of sodium:

Number of moles of sodium = mass / molar mass

Number of moles of sodium = 0.230 g / 23 g/mol

Number of moles of sodium = 0.01 mol

Enthalpy of reaction:

ΔHrxn =  2390 J / 0.01 mol

ΔHrxn = 239000 j/mol

ΔHrxn = 239 kj/mol

3 0
3 years ago
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