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Law Incorporation [45]
3 years ago
13

What is a proposed answer to a question

Physics
1 answer:
igor_vitrenko [27]3 years ago
6 0
“In the scientific method, observations lead to questions that require answers. In the scientific method, the hypothesis is a testable statement proposed to answer a question.” I hope this helps you for what your looking for
You might be interested in
What is 34 + (5) × (1.2465) written with the correct number of significant figures?
bonufazy [111]

Answer: 40

Explanation:

= 34 + 5 * 1.2465

= ‭40.2325‬

= 40

The number of significant figures in the answer should be the same as the number with the least number of significant figures that any of the digits in the equation have.

32 has 2 significant figures so the answer has to be 2 significant figures which is 40.

7 0
4 years ago
How do I find the impulse here?
quester [9]
Impulse equals to the force into the actual time period of the applied force . thus the force here given is 245.300 N and time is 0.05 thus the impulse is 12.265 Ns
3 0
4 years ago
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What is the transfer of energy by collisions between the atoms in the material
Anettt [7]
Conduction is the transfer of energy by collusion between the atoms and molecules in a material.
5 0
4 years ago
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A plastic light pipe has an index of refraction of 1.48. For total internal reflection, what is the minimum angle of incidence i
Rama09 [41]

Answer:

a) 42.52°

b) 63.98°

Explanation:

Refractive index of pipe = 1.48 = n₂

Refractive index of air = 1.0003 = n₁

\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.0003}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.676\\\Rightarrow \theta_r=42.52^{\circ}

∴ Minimum angle of incidence is 42.52°

Refractive index of water = 1.33 = n₁

\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{1.33}{1.48}\\\Rightarrow \theta_r=sin^{-1}0.899\\\Rightarrow \theta_r=63.98^{\circ}

∴ Minimum angle of incidence is 63.98°

5 0
4 years ago
Can someone help meeeeee... show how to solve it plzzzzzzzz
liubo4ka [24]
<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have a gravitation force F_{1}=16units, given by the formula written at the beginning. Let’s rename the distance r as d:

F_{1}=G\frac{m_{1}m_{2}}{d^2}     (1)

And we are asked to find the gravitation force F_{2} with a given distance of \frac{d}{2}:

F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}      

F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}     (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate G m_{1}m_{2} in both equations:

From (1):

Gm_{1}m_{2}=F_{1}{d}^{2}     (3)

From (2):

Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}     (4)

If (3)=(4):

F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}     (5)

Now we have to find F_{2}:

F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}      

F_{2}=4F_{1}     (6)

If F_{1}=16 units:

F_{2}=(4)(16 units)        

F_{2}=64 units>>>>This is the new force of attraction     

3 0
3 years ago
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