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3 years ago

What is the mechanical advantage of the machine?

Physics

2 answers:

Alekssandra [29.7K]3 years ago

8 0

Its the way the person uses the machine

trapecia [35]3 years ago

4 0

Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system.

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During sexual reproduction, each parent contributes

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Answer:

I don't understand what exactly you're asking, but this statement is true.

Explanation:

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3 years ago

What is the first step of the hydrogen fusion process?

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The first step is the fusion of hydrogen into Deuterium.

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What does "Position (m)” represent in the graph?

SCORPION-xisa [38]

Position (m)” represent the dependent variable in the graph.

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4 years ago

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Consider a satellite in a circular orbit around the Earth. If it were at an altitude equal to twice the radius of the Earth, 2RE

Elenna [48]

Answer:

$v=\sqrt{\frac{gR_E}{2}}$

Explanation:

Satellites experiment a force given by Newton's Gravitation Law:

$F=\frac{GMm}{r^2}$

where M is Earth's mass, m the satellite's mass, r the distance between their gravitational centers and G the gravitational constant.

We also know from Newton's 2nd Law that F=ma, so putting both together we will have:

$ma=\frac{GMm}{r^2}$

$a=\frac{GM}{r^2}$

If we are on the surface of the Earth, the acceleration would be g and $r=R_E$ (Earth's radius):

$g=\frac{GM}{R_E^2}$

Which we will write as:

$gR_E^2=GM$

If we are on orbit the acceleration is centripetal ( $a=\frac{v^2}{r}$ ), so we have:

$\frac{v^2}{r}=a=\frac{GM}{r^2}=\frac{gR_E^2}{r^2}$

$v^2=\frac{gR_E^2}{r}$

$v=\sqrt{\frac{gR_E^2}{r}}$

And if this orbit has a radius $r=2R_E$ we have:

$v=\sqrt{\frac{gR_E^2}{2R_E}}=\sqrt{\frac{gR_E}{2}}$

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3 years ago

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What is the area

bearhunter [10]

Answer:e3

explanation: the answer is 200

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3 years ago