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gizmo_the_mogwai [7]
3 years ago
5

If an automobile engine delivers 42.0 hp of power, how much time will it take for the engine to do 6.20 â 105 j of work? (hint:

note that one horsepower, 1 hp, is equal to 746 watts.)
Physics
1 answer:
Elena L [17]3 years ago
7 0
To be able to answer this item, we are to calculate the power that the machine could deliver from hp to kW. 

      (45 hp)(746 W/1 hp) = 33570 W

Power is the amount of energy delivered at a certain period. 

             t = (6.20 x 10^2 J)/ (33570 kJ/s)

             t = 0.01845 s
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lyudmila [28]
Is there a multiple choice?
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Please help on questions D AND E and please show working out as well so I can understand better thank you only QUESTIONS D AND E
tester [92]

Answer:

d. 87,500 J

e. 49,600 J

Explanation:

The total energy is the heat absorbed by the copper plus the heat absorbed by the water.

d)

E = m₁C₁ΔT + m₂C₂ΔT

E = (1 kg) (390 J/kg/°C) (10 °C) + (2 kg) (4180 J/kg/°C) (10 °C)

E = 87,500 J

e)

E = m₁C₁ΔT + m₂C₂ΔT

E = (2 kg) (390 J/kg/°C) (10 °C) + (1 kg) (4180 J/kg/°C) (10 °C)

E = 49,600 J

5 0
3 years ago
Một sóng cơ học có tần số 50hz lan truyền dọc theo một sợi dây rất dài biết rằng sau 5 giây sóng truyền được 1 đoạn 25m dọc theo
Oliga [24]

Answer:

10 cm

Explanation:

Được

Tần số = 50 hertz

Khoảng cách đã đi = 25 m

Thời gian đi quãng đường 25 m = 5 giây

Tốc độ của sóng = 25/5 = 5 mét trên giây

Như chúng ta biết

Bước sóng = Vận tốc / tần số

Bước sóng = 5 mét trên giây / 50 trên giây

Bước sóng = 0,1 m = 10 cm

3 0
3 years ago
A wildlife photographer uses a moderate telephoto lens of focal length 135 mm and maximum aperture f/4.00 to photograph a bear t
labwork [276]

Answer:

<h3>(A) The width x = 0.24 \times 10^{-3} m</h3><h3>(B) The new width is 1.32 \times 10^{-3} m</h3>

Explanation:

Given :

Focal length f =   135 \times 10^{-3}  m

Maximum aperture D = \frac{f}{4}

Wavelength \lambda = 550 \times 10^{-9} m

(A)

From rayleigh criterion,

  \theta = \frac{1.22 \lambda }{D}

  \theta =\frac{ 1.22 \times 550 \times 10^{-9}  }{33.75 \times 10^{-3} }

  \theta = 1.98 \times 10^{-5} rad

From angle formula,

  x = R\theta

Where R = 12 m ( given in example )

x = 12 \times 1.98 \times 10^{-5} m

x = 23.76 \times 10^{-5}

x = 0.24 \times 10^{-3} m

(B)

We know that \theta is proportional to the x and inversely proportional to the D

so we write the new width, here x is 5.5 times larger than above case

   x = 0.24 \times  10^{-3}  \times \frac{22}{4}

   x = 1.32 \times 10^{-3} m

6 0
3 years ago
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