3 years ago

A runner of 60kg accelerates at 2.0 m/s at the start of race calculate the force provided from her legs

Physics

1 answer:

vfiekz [6]3 years ago

4 0

Answer:

120 kgm/s

Explanation:

Force= mass× acceleration

= 60kg × 2.0m/s

= 120 kgm/s

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Positions B and D are 11.3 meters and 1.9 meters above the playing field, respectively. If the ball had a speed of 6.2 m/s in po

Andreyy89

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Speed of the ball in position D $=14.92 \frac{m}{s}$

<u>Explanation:</u>

Given:

Position of B=11.3 $\text { meters }$

Position of D=1.9 $\text { meters }$

Velocity of B=6.2 $\text { meters }$

To Find:

Velocity of D

Solution:

According to the formula, Velocity is given as

$V d=\sqrt{\left[V b^{2}+(2 \times g \times d y)\right]}$

$V b$ =Velocity of B

$V d$ =Velocity of D

g=acceleration due to gravity=9.8 m/s^2

$d y$ =Change in position of B and D

Substitute the all values in the above equation we get

$d y=11.3-1.9$

$V d=\sqrt{\left[6.2^{2}+(2 \times 9.8 \times(11.3-1.9))\right]}$

$=\sqrt{[38.44+(2 \times 9.8 \times(9.4))]}$

$=\sqrt{[38.44+(19.6 \times 9.4)]}$

$=\sqrt{38.44+186.24}$

$=\sqrt{222.68}$

$=14.92 \frac{m}{s}$

Result :

The velocity of D is $=14.92 \frac{m}{s}$

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